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ajit.shirsat
Group Title
A ball is thrown upwards with an initial velocity of 10 m·s−1.
Determine the maximum height reached above the thrower's hand.
Determine the time it takes the ball to reach its maximum height.
 one year ago
 one year ago
ajit.shirsat Group Title
A ball is thrown upwards with an initial velocity of 10 m·s−1. Determine the maximum height reached above the thrower's hand. Determine the time it takes the ball to reach its maximum height.
 one year ago
 one year ago

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sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Is it thrown vertically upwards?
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
If yes then, v^2 =u^2 +2as 0^2 = 10^2 + 2*(9.81) *s
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Solve for s ... where s= max height reached by the ball.
 one year ago

ajit.shirsat Group TitleBest ResponseYou've already chosen the best response.0
YA r8.......
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
To calculate time u can use: s= (u+v)/2 *t
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Or, v=u+at
 one year ago
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