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A ball is thrown upwards with an initial velocity of 10 m·s−1. Determine the maximum height reached above the thrower's hand. Determine the time it takes the ball to reach its maximum height.

Mathematics
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Is it thrown vertically upwards?
If yes then, v^2 =u^2 +2as 0^2 = 10^2 + 2*(-9.81) *s
Solve for s ... where s= max height reached by the ball.

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Other answers:

YA r8.......
To calculate time u can use: s= (u+v)/2 *t
Or, v=u+at

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