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ajit.shirsat

  • 2 years ago

A ball is thrown upwards with an initial velocity of 10 m·s−1. Determine the maximum height reached above the thrower's hand. Determine the time it takes the ball to reach its maximum height.

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  1. sauravshakya
    • 2 years ago
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    Is it thrown vertically upwards?

  2. sauravshakya
    • 2 years ago
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    If yes then, v^2 =u^2 +2as 0^2 = 10^2 + 2*(-9.81) *s

  3. sauravshakya
    • 2 years ago
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    Solve for s ... where s= max height reached by the ball.

  4. ajit.shirsat
    • 2 years ago
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    YA r8.......

  5. sauravshakya
    • 2 years ago
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    To calculate time u can use: s= (u+v)/2 *t

  6. sauravshakya
    • 2 years ago
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    Or, v=u+at

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