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A ball is thrown upwards with an initial velocity of 10 m·s−1.
Determine the maximum height reached above the thrower's hand.
Determine the time it takes the ball to reach its maximum height.
 one year ago
 one year ago
A ball is thrown upwards with an initial velocity of 10 m·s−1. Determine the maximum height reached above the thrower's hand. Determine the time it takes the ball to reach its maximum height.
 one year ago
 one year ago

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sauravshakyaBest ResponseYou've already chosen the best response.1
Is it thrown vertically upwards?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
If yes then, v^2 =u^2 +2as 0^2 = 10^2 + 2*(9.81) *s
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Solve for s ... where s= max height reached by the ball.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
To calculate time u can use: s= (u+v)/2 *t
 one year ago
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