A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
ajit.shirsat
 2 years ago
A ball is thrown upwards with an initial velocity of 10 m·s−1.
Determine the maximum height reached above the thrower's hand.
Determine the time it takes the ball to reach its maximum height.
ajit.shirsat
 2 years ago
A ball is thrown upwards with an initial velocity of 10 m·s−1. Determine the maximum height reached above the thrower's hand. Determine the time it takes the ball to reach its maximum height.

This Question is Closed

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1Is it thrown vertically upwards?

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1If yes then, v^2 =u^2 +2as 0^2 = 10^2 + 2*(9.81) *s

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1Solve for s ... where s= max height reached by the ball.

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.1To calculate time u can use: s= (u+v)/2 *t
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.