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anonymous
 4 years ago
How to find the area under this curve?
anonymous
 4 years ago
How to find the area under this curve?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A bicyclist pedals along a straight road with velocity, v, given in the figure below. She starts 3 miles from a lake; positive velocities take her away from the lake and negative velocities take her toward the lake. http://i.imgur.com/lhJQd.png Approximately how far away is she at this time? Give a best estimate.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The time is one hour...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just count the number of squares

tkhunny
 4 years ago
Best ResponseYou've already chosen the best response.0Please define "under". That first 20 is troublesome.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It includes both the negative and positive velocities, so not exactly under for both

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00 is the x axis of course

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They basically want you to count squares here.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That seems too simple. What would be the units I would use?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The count the number of square when it is above, and subtract from the the number of square when it is below.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The square is 10mph time is 1 h So the result is 10 miles for each square

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Keep it simple, they asked for an approximation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What should I do for the squares that aren't whole?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It seems a bit tricky go guess

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you want to make it more complicated, then just roughly estimate how much of a square it is.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, I will try my best to approximate it. Thank you
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