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gaby236 Group Title

http://media01.owotw.com/o_alg02_2011/5/406.gif

  • 2 years ago
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  1. gaby236 Group Title
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    i need help

    • 2 years ago
  2. gaby236 Group Title
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    solve for y

    • 2 years ago
  3. gaby236 Group Title
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    -2/5 -9/80 -3.5 i think a

    • 2 years ago
  4. tkhunny Group Title
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    1) Wite down \[y \ne 0\]2) Multiply everything by y. 3) Multiply everything by 7 4) Multiply everything by 3 5) Multiply everything by 2 There are other ways to proceed. This is just one with what I hope is an obviuos goal.

    • 2 years ago
  5. jayz657 Group Title
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    lets simplify the left side first factor in the 3 and get 3y+ 21 so you have (3y + 21 / 7y) -(4y -7/6) find common denominator so it will be like this [6(3y+21) - 7y(4y -7) ] / 7y simplifying [18y + 126 - 28y^2 + 49 ] / 7y [ -28y^2 + 18y + 175 ]/7y now lets simplify right side multiply in the 2 14y -2 / 21 find common denominator [21(7y+10) - 3y(14y - 2)] / 63y simplify [147y + 120 - 42y^2 + 6y] / 63y [-42y^2 + 153y + 120 ] / 63y now your equation looks like this: [-28y^2 + 18y + 175]/7y = [-42y^2 + 153y + 120]/63y cross multiply 63y[-28y^2 + 18y + 175] = 7y [-42y^2 + 153y + 120] cancel out 7y on both sides 9[-28y^2 + 18y + 175] = -42y^2 + 153y + 120 multiply in 9 -252y^2 + 162y + 1575 = -42y^2 + 153y + 120 simplify -210y^2 - 9y + 1455 = 0 factor using quadrictic formula should give you your answer

    • 2 years ago
  6. gaby236 Group Title
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    is -2/5

    • 2 years ago
  7. gaby236 Group Title
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    is correct my answer

    • 2 years ago
  8. jayz657 Group Title
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    sorry i might of made a mistake in that math but the process of doing it is correct

    • 2 years ago
  9. gaby236 Group Title
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    @RadEn

    • 2 years ago
  10. gaby236 Group Title
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    @robtobey

    • 2 years ago
  11. RadEn Group Title
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    wolfram told me the answer is -2/5 :) u are correct http://www.wolframalpha.com/input/?i=%283%28y%2B7%29%2F7y%29-%28%284y-7%29%2F6%29%3D%28%287y%2B10%29%2F3y%29-%282%287y-1%29%2F21%29&dataset=

    • 2 years ago
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