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gaby236 Group TitleBest ResponseYou've already chosen the best response.0
i need help
 2 years ago

gaby236 Group TitleBest ResponseYou've already chosen the best response.0
solve for y
 2 years ago

gaby236 Group TitleBest ResponseYou've already chosen the best response.0
2/5 9/80 3.5 i think a
 2 years ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
1) Wite down \[y \ne 0\]2) Multiply everything by y. 3) Multiply everything by 7 4) Multiply everything by 3 5) Multiply everything by 2 There are other ways to proceed. This is just one with what I hope is an obviuos goal.
 2 years ago

jayz657 Group TitleBest ResponseYou've already chosen the best response.0
lets simplify the left side first factor in the 3 and get 3y+ 21 so you have (3y + 21 / 7y) (4y 7/6) find common denominator so it will be like this [6(3y+21)  7y(4y 7) ] / 7y simplifying [18y + 126  28y^2 + 49 ] / 7y [ 28y^2 + 18y + 175 ]/7y now lets simplify right side multiply in the 2 14y 2 / 21 find common denominator [21(7y+10)  3y(14y  2)] / 63y simplify [147y + 120  42y^2 + 6y] / 63y [42y^2 + 153y + 120 ] / 63y now your equation looks like this: [28y^2 + 18y + 175]/7y = [42y^2 + 153y + 120]/63y cross multiply 63y[28y^2 + 18y + 175] = 7y [42y^2 + 153y + 120] cancel out 7y on both sides 9[28y^2 + 18y + 175] = 42y^2 + 153y + 120 multiply in 9 252y^2 + 162y + 1575 = 42y^2 + 153y + 120 simplify 210y^2  9y + 1455 = 0 factor using quadrictic formula should give you your answer
 2 years ago

gaby236 Group TitleBest ResponseYou've already chosen the best response.0
is correct my answer
 2 years ago

jayz657 Group TitleBest ResponseYou've already chosen the best response.0
sorry i might of made a mistake in that math but the process of doing it is correct
 2 years ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
wolfram told me the answer is 2/5 :) u are correct http://www.wolframalpha.com/input/?i=%283%28y%2B7%29%2F7y%29%28%284y7%29%2F6%29%3D%28%287y%2B10%29%2F3y%29%282%287y1%29%2F21%29&dataset=
 2 years ago
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