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angelleighh

Solve the system of equations. y = 2x² – 3 y = 3x – 1 (1 point) no solution (–1/2, 5), (2, –5/2) (–1/2, –5/2), (2, 5) (1/2,5/2 ), (2, 5)

  • one year ago
  • one year ago

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  1. ChmE
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    set them equal to each other and solve for x

    • one year ago
  2. ChmE
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    Once you have x you can plug each solution into the bottom equation and solve

    • one year ago
  3. ChmE
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    for y

    • one year ago
  4. angelleighh
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    I'm so confused on how to do this but alright thanks.

    • one year ago
  5. angelleighh
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    Wait, it would be (–1/2, –5/2), (2, 5) i think.

    • one year ago
  6. ChmE
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    I'll show you the steps. The quetion is referring to when these equations intersect or in other words equal eachother. 2x^2 - 3 = 3x - 1 This is going to be a quadratic so we have to set it equal to zero. 2x^2 - 3x - 3 + 1 = 0 2x^2 - 3x - 2 = 0 we can use the quadratic formula to solve for x or factor it. (2x+1)(x-2)=0 is the factored form. now we know that the equation equals zero when x = 2 and -1/2. (just saw your post, you are correct) Do you want me to still show you the quadratic way of solving it or do you know that?

    • one year ago
  7. angelleighh
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    Thank you, i got it from there.

    • one year ago
  8. ChmE
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    yw

    • one year ago
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