## angelleighh Group Title Solve the system of equations. y = 2x² – 3 y = 3x – 1 (1 point) no solution (–1/2, 5), (2, –5/2) (–1/2, –5/2), (2, 5) (1/2,5/2 ), (2, 5) 2 years ago 2 years ago

1. ChmE

set them equal to each other and solve for x

2. ChmE

Once you have x you can plug each solution into the bottom equation and solve

3. ChmE

for y

4. angelleighh

I'm so confused on how to do this but alright thanks.

5. angelleighh

Wait, it would be (–1/2, –5/2), (2, 5) i think.

6. ChmE

I'll show you the steps. The quetion is referring to when these equations intersect or in other words equal eachother. 2x^2 - 3 = 3x - 1 This is going to be a quadratic so we have to set it equal to zero. 2x^2 - 3x - 3 + 1 = 0 2x^2 - 3x - 2 = 0 we can use the quadratic formula to solve for x or factor it. (2x+1)(x-2)=0 is the factored form. now we know that the equation equals zero when x = 2 and -1/2. (just saw your post, you are correct) Do you want me to still show you the quadratic way of solving it or do you know that?

7. angelleighh

Thank you, i got it from there.

8. ChmE

yw