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angelleighh
Group Title
Solve the system of equations.
y = 2x² – 3
y = 3x – 1 (1 point)
no solution
(–1/2, 5), (2, –5/2)
(–1/2, –5/2), (2, 5)
(1/2,5/2 ), (2, 5)
 2 years ago
 2 years ago
angelleighh Group Title
Solve the system of equations. y = 2x² – 3 y = 3x – 1 (1 point) no solution (–1/2, 5), (2, –5/2) (–1/2, –5/2), (2, 5) (1/2,5/2 ), (2, 5)
 2 years ago
 2 years ago

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ChmE Group TitleBest ResponseYou've already chosen the best response.0
set them equal to each other and solve for x
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
Once you have x you can plug each solution into the bottom equation and solve
 2 years ago

angelleighh Group TitleBest ResponseYou've already chosen the best response.0
I'm so confused on how to do this but alright thanks.
 2 years ago

angelleighh Group TitleBest ResponseYou've already chosen the best response.0
Wait, it would be (–1/2, –5/2), (2, 5) i think.
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
I'll show you the steps. The quetion is referring to when these equations intersect or in other words equal eachother. 2x^2  3 = 3x  1 This is going to be a quadratic so we have to set it equal to zero. 2x^2  3x  3 + 1 = 0 2x^2  3x  2 = 0 we can use the quadratic formula to solve for x or factor it. (2x+1)(x2)=0 is the factored form. now we know that the equation equals zero when x = 2 and 1/2. (just saw your post, you are correct) Do you want me to still show you the quadratic way of solving it or do you know that?
 2 years ago

angelleighh Group TitleBest ResponseYou've already chosen the best response.0
Thank you, i got it from there.
 2 years ago
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