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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{\sin x+1 } \frac{ 1 }{ sinx1 } = \frac{ 2 }{ \cos^{2}x }\]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x }\]
 2 years ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You're going to have to add the ones on the left before you see it.
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean ? :S
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
\[\Large \frac{a}{b}  \frac{c}{d} = \frac{adcb}{bd} \]
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
for the right side i get this : \[\huge \frac{ (sinx1)(sinx+1) }{ 1\sin^2x }\]
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
dont make your life hard combine the left hand side into 1 fraction first
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
then multiply the denominators to remove the fraction
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
then it would be extremely easy to solve
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]
 2 years ago
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