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burhan101Best ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{\sin x+1 } \frac{ 1 }{ sinx1 } = \frac{ 2 }{ \cos^{2}x }\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x }\]
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
You're going to have to add the ones on the left before you see it.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
what do you mean ? :S
 one year ago

wioBest ResponseYou've already chosen the best response.0
\[\Large \frac{a}{b}  \frac{c}{d} = \frac{adcb}{bd} \]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
for the right side i get this : \[\huge \frac{ (sinx1)(sinx+1) }{ 1\sin^2x }\]
 one year ago

irkizBest ResponseYou've already chosen the best response.1
dont make your life hard combine the left hand side into 1 fraction first
 one year ago

irkizBest ResponseYou've already chosen the best response.1
then multiply the denominators to remove the fraction
 one year ago

irkizBest ResponseYou've already chosen the best response.1
then it would be extremely easy to solve
 one year ago

irkizBest ResponseYou've already chosen the best response.1
when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]
 one year ago
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