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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{\sin x+1 } \frac{ 1 }{ sinx1 } = \frac{ 2 }{ \cos^{2}x }\]
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x }\]
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
You're going to have to add the ones on the left before you see it.
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean ? :S
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
\[\Large \frac{a}{b}  \frac{c}{d} = \frac{adcb}{bd} \]
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
for the right side i get this : \[\huge \frac{ (sinx1)(sinx+1) }{ 1\sin^2x }\]
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
dont make your life hard combine the left hand side into 1 fraction first
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
then multiply the denominators to remove the fraction
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
then it would be extremely easy to solve
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]
 one year ago
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