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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ 1 }{\sin x+1 } \frac{ 1 }{ sinx1 } = \frac{ 2 }{ \cos^{2}x }\]

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x }\]

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.0You're going to have to add the ones on the left before you see it.

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0what do you mean ? :S

wio
 2 years ago
Best ResponseYou've already chosen the best response.0\[\Large \frac{a}{b}  \frac{c}{d} = \frac{adcb}{bd} \]

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0for the right side i get this : \[\huge \frac{ (sinx1)(sinx+1) }{ 1\sin^2x }\]

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1dont make your life hard combine the left hand side into 1 fraction first

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1then multiply the denominators to remove the fraction

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1then it would be extremely easy to solve

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.1when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]
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