anonymous
  • anonymous
Trig identities
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\huge \frac{ 1 }{\sin x+1 }- \frac{ 1 }{ sinx-1 } = \frac{ 2 }{ \cos^{2}x }\]
anonymous
  • anonymous
\[\huge \frac{ 1 }{ sinx+1 } - \frac{ 1 }{ sinx-1 } = \frac{ 2 }{ 1-\sin^2x }\]
tkhunny
  • tkhunny
You're going to have to add the ones on the left before you see it.

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anonymous
  • anonymous
what do you mean ? :S
anonymous
  • anonymous
\[\Large \frac{a}{b} - \frac{c}{d} = \frac{ad-cb}{bd} \]
anonymous
  • anonymous
for the right side i get this : \[\huge \frac{ (sinx-1)-(sinx+1) }{ 1-\sin^2x }\]
anonymous
  • anonymous
dont make your life hard combine the left hand side into 1 fraction first
anonymous
  • anonymous
then multiply the denominators to remove the fraction
anonymous
  • anonymous
then it would be extremely easy to solve
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]

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