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anonymous
 3 years ago
Trig identities
anonymous
 3 years ago
Trig identities

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ 1 }{\sin x+1 } \frac{ 1 }{ sinx1 } = \frac{ 2 }{ \cos^{2}x }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\huge \frac{ 1 }{ sinx+1 }  \frac{ 1 }{ sinx1 } = \frac{ 2 }{ 1\sin^2x }\]

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.0You're going to have to add the ones on the left before you see it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do you mean ? :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Large \frac{a}{b}  \frac{c}{d} = \frac{adcb}{bd} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for the right side i get this : \[\huge \frac{ (sinx1)(sinx+1) }{ 1\sin^2x }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dont make your life hard combine the left hand side into 1 fraction first

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then multiply the denominators to remove the fraction

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then it would be extremely easy to solve

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when u make the LHS into one fraction, u will get something like \[\frac{ a }{ b }=\frac{ c }{ d }\] \[ad = cb\]
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