## anonymous 3 years ago Trig identities

1. anonymous

$\huge \frac{ 1 }{\sin x+1 }- \frac{ 1 }{ sinx-1 } = \frac{ 2 }{ \cos^{2}x }$

2. anonymous

$\huge \frac{ 1 }{ sinx+1 } - \frac{ 1 }{ sinx-1 } = \frac{ 2 }{ 1-\sin^2x }$

3. tkhunny

You're going to have to add the ones on the left before you see it.

4. anonymous

what do you mean ? :S

5. anonymous

$\Large \frac{a}{b} - \frac{c}{d} = \frac{ad-cb}{bd}$

6. anonymous

for the right side i get this : $\huge \frac{ (sinx-1)-(sinx+1) }{ 1-\sin^2x }$

7. anonymous

dont make your life hard combine the left hand side into 1 fraction first

8. anonymous

then multiply the denominators to remove the fraction

9. anonymous

then it would be extremely easy to solve

10. anonymous

ohhh

11. anonymous

when u make the LHS into one fraction, u will get something like $\frac{ a }{ b }=\frac{ c }{ d }$ $ad = cb$