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anonymous
 4 years ago
Use the Rational Root Theorem to list all possible rational roots of the polynomial equation x3 – x2 – x – 3 = 0. Do not find the actual roots. (1 point)
–3, –1, 1, 3
1, 3
–33
no roots
anonymous
 4 years ago
Use the Rational Root Theorem to list all possible rational roots of the polynomial equation x3 – x2 – x – 3 = 0. Do not find the actual roots. (1 point) –3, –1, 1, 3 1, 3 –33 no roots

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it is a am i right yes or no

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a_n = 1 \quad a_0 = 3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \pm \frac{1,3}{1} = 1, 3, 1, 3 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you're right, but what matters is the process you used.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok can u check another one for me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What does Descartes's Rule of Signs tell you about the real roots of the polynomial? –2x3 + 3x2 – 5x – 2 = 0 (1 point) There is one positive root and either 2 or 0 negative roots. There are either 2 or 0 positive roots and there are either 2 or 0 negative roots. There is one positive root and one negative root. There are either 2 or 0 positive roots and one negative root. i think it c

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well it has 3 roots. We know it has 2 or 0 positive roots.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0aThere is one positive root and either 2 or 0 negative roots. bThere are either 2 or 0 positive roots and there are either 2 or 0 negative roots. cThere is one positive root and one negative root. dThere are either 2 or 0 positive roots and one negative root.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Find a thirddegree polynomial equation with rational coefficients that has roots –4 and 6 + i. (1 point) x3 – 8x2 – 11x + 148 = 0 x3 – 8x2 – 12x + 37 = 0 x3 – 12x2 + 37x = 0 x3 – 8x2 – 11x = 0 i think this one is b or a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Obviously it is a or b, since 0 is not a root.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so which one do u think it is im going with a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can't you just plug 4 into one of them to find out?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats number 2 to this ?
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