anonymous
  • anonymous
Use the Rational Root Theorem to list all possible rational roots of the polynomial equation x3 – x2 – x – 3 = 0. Do not find the actual roots. (1 point) –3, –1, 1, 3 1, 3 –33 no roots
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i think it is a am i right yes or no
anonymous
  • anonymous
\[a_n = 1 \quad a_0 = -3\]
anonymous
  • anonymous
\[ \pm \frac{1,3}{1} = 1, 3, -1, -3 \]

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anonymous
  • anonymous
you're right, but what matters is the process you used.
anonymous
  • anonymous
ok can u check another one for me
anonymous
  • anonymous
What does Descartes's Rule of Signs tell you about the real roots of the polynomial? –2x3 + 3x2 – 5x – 2 = 0 (1 point) There is one positive root and either 2 or 0 negative roots. There are either 2 or 0 positive roots and there are either 2 or 0 negative roots. There is one positive root and one negative root. There are either 2 or 0 positive roots and one negative root. i think it c
anonymous
  • anonymous
@wio am a right
anonymous
  • anonymous
Well it has 3 roots. We know it has 2 or 0 positive roots.
anonymous
  • anonymous
so its d
anonymous
  • anonymous
you didn't list d
anonymous
  • anonymous
aThere is one positive root and either 2 or 0 negative roots. bThere are either 2 or 0 positive roots and there are either 2 or 0 negative roots. cThere is one positive root and one negative root. dThere are either 2 or 0 positive roots and one negative root.
anonymous
  • anonymous
d looks best.
anonymous
  • anonymous
ok i have 1 more
anonymous
  • anonymous
Find a third-degree polynomial equation with rational coefficients that has roots –4 and 6 + i. (1 point) x3 – 8x2 – 11x + 148 = 0 x3 – 8x2 – 12x + 37 = 0 x3 – 12x2 + 37x = 0 x3 – 8x2 – 11x = 0 i think this one is b or a
anonymous
  • anonymous
Obviously it is a or b, since 0 is not a root.
anonymous
  • anonymous
so which one do u think it is im going with a
anonymous
  • anonymous
can't you just plug 4 into one of them to find out?
anonymous
  • anonymous
whats number 2 to this ?
anonymous
  • anonymous
a a d a d

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