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 2 years ago
Zach wrote the formula w(w1)(5w + 4) for the volume of a rectangular prism he is designing, with width w, which is always has a positive value greater than 1. Find the product and then classify this polynomial by degree and by number of terms.
Choices:)
A.) 5w^5  w^4  4w^3; quintic trinomial
B.) 20w^2; quadratic monomial
C.) 5w^3  w^2  4w; cubic trinomial
D.) 5w^4  w^3  4w^2; quartic trinomial
 2 years ago
Zach wrote the formula w(w1)(5w + 4) for the volume of a rectangular prism he is designing, with width w, which is always has a positive value greater than 1. Find the product and then classify this polynomial by degree and by number of terms. Choices:) A.) 5w^5  w^4  4w^3; quintic trinomial B.) 20w^2; quadratic monomial C.) 5w^3  w^2  4w; cubic trinomial D.) 5w^4  w^3  4w^2; quartic trinomial

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malical
 2 years ago
Best ResponseYou've already chosen the best response.1Well, first I would factor the (w1)(5w+4) and the multiple the result by the remaining w. See which answer choice you get.

Brooke2013
 2 years ago
Best ResponseYou've already chosen the best response.0When you factor (w1)(5w+4) without multiplying the remaining with the w do you get 5w^2  4w + 5w + 4

malical
 2 years ago
Best ResponseYou've already chosen the best response.1Not quite. The first and last terms are correct but you need to: (1)(5w) and (4)(w) In other words, look at you signs. Also, you should add those two together because they share a common variable (w to the 1st power). Now multiply that equation by w and you should see your answer appear.

Brooke2013
 2 years ago
Best ResponseYou've already chosen the best response.0is the answer C ? 5w^3  w^2  4w; cubic trinomial

malical
 2 years ago
Best ResponseYou've already chosen the best response.1I dunno. Can we give proof for why?

Brooke2013
 2 years ago
Best ResponseYou've already chosen the best response.0Because that's what I got when I figured out the problem, I was just making sure it's right.

Brooke2013
 2 years ago
Best ResponseYou've already chosen the best response.0Alright Thank you :)
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