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anonymous
 4 years ago
In a geometric sequence, the term an+1 can be smaller than the term an.
true or false?
anonymous
 4 years ago
In a geometric sequence, the term an+1 can be smaller than the term an. true or false?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are u sure?? how did u know so fast?? lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so n ranges from 0 to 1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if the interval is (1) that makes it alternating

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it will be smaller and bigger alternatingly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(1)^ 2 is positive, (2) ^ 3 is negative

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1if the common ratio r <1 then each term is smaller that the previous

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there are a few cases yeah. if the sequence convergerges or if the sign alternates

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait so its TRUE then???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i said wait coz my explanation was incomplete

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay haha :P thanks!!! so its definitely TRUE right?

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1if the absolute value of r is less than 1 r < 1 the the geometric series will have a limiting sum...

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1just to clarify things... n is used for the term number... and r is used for the common ratio ( or multiplication constant)... just to avoid confusion.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k thanks for all the help y'all!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah. \[ar ^{n}\] if r < 1 it converges and if r is negative, it alternates

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1not quite a term in a geometric series is found using \[T_{n} = ar^{n 1}\] n is the term number, T is the Term a is the 1st term and r is the common ratio... please get it right @irkiz

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k thanks for all the help y'all!
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