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iheartfood Group Title

In a geometric sequence, the term an+1 can be smaller than the term an. true or false?

  • 2 years ago
  • 2 years ago

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  1. irkiz Group Title
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    true

    • 2 years ago
  2. irkiz Group Title
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    if n is < 1

    • 2 years ago
  3. iheartfood Group Title
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    are u sure?? how did u know so fast?? lol

    • 2 years ago
  4. irkiz Group Title
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    as in |n| < 1

    • 2 years ago
  5. irkiz Group Title
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    so n ranges from 0 to 1

    • 2 years ago
  6. irkiz Group Title
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    oops

    • 2 years ago
  7. irkiz Group Title
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    wait

    • 2 years ago
  8. iheartfood Group Title
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    oh okay

    • 2 years ago
  9. irkiz Group Title
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    if the interval is (-1) that makes it alternating

    • 2 years ago
  10. irkiz Group Title
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    so it will be smaller and bigger alternatingly

    • 2 years ago
  11. irkiz Group Title
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    (-1)^ 2 is positive, (-2) ^ 3 is negative

    • 2 years ago
  12. iheartfood Group Title
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    so this is FALSE?

    • 2 years ago
  13. irkiz Group Title
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    (-2)^2 i mean

    • 2 years ago
  14. campbell_st Group Title
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    if the common ratio r <1 then each term is smaller that the previous

    • 2 years ago
  15. irkiz Group Title
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    there are a few cases yeah. if the sequence convergerges or if the sign alternates

    • 2 years ago
  16. iheartfood Group Title
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    wait so its TRUE then???

    • 2 years ago
  17. irkiz Group Title
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    yup its true

    • 2 years ago
  18. irkiz Group Title
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    i said wait coz my explanation was incomplete

    • 2 years ago
  19. iheartfood Group Title
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    oh okay haha :P thanks!!! so its definitely TRUE right?

    • 2 years ago
  20. campbell_st Group Title
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    if the absolute value of r is less than 1 |r| < 1 the the geometric series will have a limiting sum...

    • 2 years ago
  21. campbell_st Group Title
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    just to clarify things... n is used for the term number... and r is used for the common ratio ( or multiplication constant)... just to avoid confusion.

    • 2 years ago
  22. iheartfood Group Title
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    k thanks for all the help y'all!

    • 2 years ago
  23. irkiz Group Title
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    yeah. \[ar ^{n}\] if |r| < 1 it converges and if r is negative, it alternates

    • 2 years ago
  24. campbell_st Group Title
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    not quite a term in a geometric series is found using \[T_{n} = ar^{n -1}\] n is the term number, T is the Term a is the 1st term and r is the common ratio... please get it right @irkiz

    • 2 years ago
  25. iheartfood Group Title
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    k thanks for all the help y'all!

    • 2 years ago
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