A druggist has two mixtures of a certain chemical and water, one containing 10% of the chemical and the other containing 40% of the chemical. How much of each mixture should he use to make 10 ounces that contain 25% of the chemical?
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x+y = 10
.1x + .4y = (.25)10
?? what about 7.5
solve system using substitution
y = 10-x
--> .1x +.4(10-x) = 2.5
solve for x
answer is 2.5
no...show your steps so i know what you did wrong
@dumbcow my answer is 1
no, by plugging 1 in you can see that both sides will not equal each other
seems like you are guessing
okey men isx ounces of 10% soln mixed with (10 – x) ounces of 40% soln. as total final volume is 10 ounces
amount of chemical in x ounces = 0.1x
amount of chemical in (10 – x) ounces = 0.4(10 – x) = 4 – 0.4x
amount of chemical in 10 ounces = 10 × 0.25 = 2.5
0.1x + 4 – 0.4x = 2.5
0.3x = 1.5
x = 5 ounces of 10% mixed with
(10 – 5) = 5 ounces of 40% to give 10 ounces of 25%
yes solution is (5,5)
how do you go from guessing to writing a well laid out solution ...haha