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Logarithm Question!!!

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Evaluate in terms of p \[\log_{c} b\] if ... \[\log_{b}a =p \] and c=a^2
put a = \(\sqrt c\) in that and tell me what u get ?
log _b (root c) = p

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right , now use the property that \(\log x^y=y \log x\) so what will be \(\log_b c^{1/2} = ? \)
1/2 (log_b (c))
right, that is p, so what is (log_b (c)) = ?
what a fun problem...i won't spoil the solution and let hartnn explain the steps
thats correct. then use the property that \(\huge \log_xy=\frac{\log y}{\log x} = \frac{1}{\log_yx}\)
(log_b (c)) = 2p so whats (log_c (b)) = ?
lol i am not fimiliar with that property.. but it equals 1/(2p)
yes, 1/(2p) is correct. its one of the very useful properties of log. u want a list of all the log properties ?
yes please XD
thank you!
welcome ^_^

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