## Schrodinger 3 years ago I really have no clue how to solve this. "Given 360.5g of hot tea at 80 (C), what mass of ice at 0 (C) must be added to obtain iced tea at 10.5 (C)? The specific heat of the tea is 4.18, and the heat of fusion for ice is 6.01 kj/mol.

1. augusto.h

(tea) mass*spec heat*T = (water) m*heat fusion

2. Schrodinger

Could you explain in words how you would arrive at the point/how i'm supposed to know that association? Thanks.

3. augusto.h

Actually I think there is something wrong because tea doesn't freeze at 10,5ºC - 1 atm. Unless the pressure is other. If so you will need the heat of fusion of tea as well.

4. augusto.h

Are you sure about the question?

5. Schrodinger

Let me double check: I'll directly copy/paste it to make sure there aren't any possible errors on my part: "Given 360.5 of hot tea at 80.0, what mass of ice at 0 must be added to obtain iced tea at 10.5? The specific heat of the tea is 4.18 , and for ice is +6.01 ."

6. augusto.h

Well I don't know. It seems to me there is lack of info. I would do this. Calculate the hole energy for the tea process. Q total = Q1 (T80->Tfusion) + Q2 (fusion) + Q3 (Tfusion->T10.5 if 10.5 is not the fusion T o f tea). Then you use this energy to calculate the mass of water Q = m*L where L is 6.01kj/mol