I really have no clue how to solve this. "Given 360.5g of hot tea at 80 (C), what mass of ice at 0 (C) must be added to obtain iced tea at 10.5 (C)? The specific heat of the tea is 4.18, and the heat of fusion for ice is 6.01 kj/mol.

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(tea) mass*spec heat*T = (water) m*heat fusion

Could you explain in words how you would arrive at the point/how i'm supposed to know that association? Thanks.

Actually I think there is something wrong because tea doesn't freeze at 10,5ÂșC - 1 atm. Unless the pressure is other. If so you will need the heat of fusion of tea as well.

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