I really have no clue how to solve this.
"Given 360.5g of hot tea at 80 (C), what mass of ice at 0 (C) must be added to obtain iced tea at 10.5 (C)? The specific heat of the tea is 4.18, and the heat of fusion for ice is 6.01 kj/mol.

Hey! We 've verified this expert answer for you, click below to unlock the details :)

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

(tea) mass*spec heat*T = (water) m*heat fusion

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.