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Mathematics
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\[\int\limits \frac{ lnx }{ x }\]
Whos feelin brave? :D
I'm thinking by parts...

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Other answers:

u du
do it by substitution, let lnx= u
haha, oh yeah, I overthought it :P
Can U be lnx ? It's above the line
so?
|dw:1353166961045:dw|
|dw:1353035523772:dw|
Put ln(x) = u So: \(\frac{1}{x} \cdot dx =du\)
Thank you guys
Just try and if you face any problem, then do ask us...
Wait, can you expand on that for me? I have \[dx = \frac{ du }{ 1/x }\]
Are you converting a simple solution to hard one??
Looks like it xD
|dw:1353167337486:dw|
Sorry, my handwriting is not too good..
Is this a direct manipulation or a substitution?
Is this not Substitution ?? We are substituting u in place of x..
Ah, ok, so lnx. Differentiation of ln = 1 over So 1/x right?
Yes..
\[\frac{d}{dx}\ln(x) = \frac{1}{x}\]
So, let me just clarify. lnx / x = 1/x?
Where does the x under the line go?
See : \[\ln(x) = u\] Right ??
Yes
Now take derivative both the sides and tell what did you get??
Next, i've been taught to do du/dx
1/x . dx
Write them properly.. with LHS and RHS..
Little lost here, sorry :(
1/x . dx = du
Do you know how it came??
Yes i get this.
What is the next step?
Just use this to substitute these values in your question..
I think the way i've been taught is conflicting... I usually write dx = du / 1/x
If substituting

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