hba 3 years ago Equation of a circle with center (-3,5) and radius 7 is :

1. hba

@waterineyes

2. Nurali

the standard equation of a circle: (x-h)^2 + (y-k)^2 = r^2 given r=7 c(5,-3) (x-5)^2+(y-(-3))^2=7^2 (x-5)^2+(y+3)^2=49 answer

3. hba

@waterineyes I got x^2+y^2+6x-10y-15=0

4. waterineyes

What is center??

5. hba

Note that i used the formula (x-a)^2+(y-b)^2=r^2 @waterineyes

6. waterineyes

Center is (-3,5) and you are using (5,-3) Any special reason??

7. hba

The center (a,b)=(-3,5) and r=7

8. waterineyes

Forget the formula.. Check once again for your solution..

9. hba

I am right :D

10. waterineyes

Shouldn't it be : \((x+3)^2 + (y-5)^2 = 7^2\) ??

11. hba

I am not using Nuralis Formula Dude i have solved it right :D

12. hba

@waterineyes And I got x^2+y^2+6x-10y-15=0

13. waterineyes

Explain to me what are you doing..

14. hba

@waterineyes (x+3)^2+(y-5)^2=7^2 x^2+6x+9+y^2-10y+25=49 x^2+y^2+6x-10y-15=0

15. waterineyes

Oh my God.. Sorry, I was thinking that, that was your post.. Really sorry..

16. waterineyes

That was of Nurali..

17. hba

Yeah lol :D Thanks anyway :)

18. waterineyes

Yes you are right..

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