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hba
 3 years ago
Equation of a circle with center (3,5) and radius 7 is :
hba
 3 years ago
Equation of a circle with center (3,5) and radius 7 is :

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the standard equation of a circle: (xh)^2 + (yk)^2 = r^2 given r=7 c(5,3) (x5)^2+(y(3))^2=7^2 (x5)^2+(y+3)^2=49 answer

hba
 3 years ago
Best ResponseYou've already chosen the best response.1@waterineyes I got x^2+y^2+6x10y15=0

hba
 3 years ago
Best ResponseYou've already chosen the best response.1Note that i used the formula (xa)^2+(yb)^2=r^2 @waterineyes

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Center is (3,5) and you are using (5,3) Any special reason??

hba
 3 years ago
Best ResponseYou've already chosen the best response.1The center (a,b)=(3,5) and r=7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Forget the formula.. Check once again for your solution..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Shouldn't it be : \((x+3)^2 + (y5)^2 = 7^2\) ??

hba
 3 years ago
Best ResponseYou've already chosen the best response.1I am not using Nuralis Formula Dude i have solved it right :D

hba
 3 years ago
Best ResponseYou've already chosen the best response.1@waterineyes And I got x^2+y^2+6x10y15=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Explain to me what are you doing..

hba
 3 years ago
Best ResponseYou've already chosen the best response.1@waterineyes (x+3)^2+(y5)^2=7^2 x^2+6x+9+y^210y+25=49 x^2+y^2+6x10y15=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh my God.. Sorry, I was thinking that, that was your post.. Really sorry..

hba
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah lol :D Thanks anyway :)
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