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  • hba

Equation of a circle with center (-3,5) and radius 7 is :

Mathematics
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  • hba
the standard equation of a circle: (x-h)^2 + (y-k)^2 = r^2 given r=7 c(5,-3) (x-5)^2+(y-(-3))^2=7^2 (x-5)^2+(y+3)^2=49 answer
  • hba
@waterineyes I got x^2+y^2+6x-10y-15=0

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Other answers:

What is center??
  • hba
Note that i used the formula (x-a)^2+(y-b)^2=r^2 @waterineyes
Center is (-3,5) and you are using (5,-3) Any special reason??
  • hba
The center (a,b)=(-3,5) and r=7
Forget the formula.. Check once again for your solution..
  • hba
I am right :D
Shouldn't it be : \((x+3)^2 + (y-5)^2 = 7^2\) ??
  • hba
I am not using Nuralis Formula Dude i have solved it right :D
  • hba
@waterineyes And I got x^2+y^2+6x-10y-15=0
Explain to me what are you doing..
  • hba
@waterineyes (x+3)^2+(y-5)^2=7^2 x^2+6x+9+y^2-10y+25=49 x^2+y^2+6x-10y-15=0
Oh my God.. Sorry, I was thinking that, that was your post.. Really sorry..
That was of Nurali..
  • hba
Yeah lol :D Thanks anyway :)
Yes you are right..

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