Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

hba Group Title

Equation of a circle with center (-3,5) and radius 7 is :

  • 2 years ago
  • 2 years ago

  • This Question is Closed
  1. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @waterineyes

    • 2 years ago
  2. Nurali Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the standard equation of a circle: (x-h)^2 + (y-k)^2 = r^2 given r=7 c(5,-3) (x-5)^2+(y-(-3))^2=7^2 (x-5)^2+(y+3)^2=49 answer

    • 2 years ago
  3. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @waterineyes I got x^2+y^2+6x-10y-15=0

    • 2 years ago
  4. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    What is center??

    • 2 years ago
  5. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Note that i used the formula (x-a)^2+(y-b)^2=r^2 @waterineyes

    • 2 years ago
  6. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Center is (-3,5) and you are using (5,-3) Any special reason??

    • 2 years ago
  7. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    The center (a,b)=(-3,5) and r=7

    • 2 years ago
  8. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Forget the formula.. Check once again for your solution..

    • 2 years ago
  9. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I am right :D

    • 2 years ago
  10. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Shouldn't it be : \((x+3)^2 + (y-5)^2 = 7^2\) ??

    • 2 years ago
  11. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I am not using Nuralis Formula Dude i have solved it right :D

    • 2 years ago
  12. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @waterineyes And I got x^2+y^2+6x-10y-15=0

    • 2 years ago
  13. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Explain to me what are you doing..

    • 2 years ago
  14. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    @waterineyes (x+3)^2+(y-5)^2=7^2 x^2+6x+9+y^2-10y+25=49 x^2+y^2+6x-10y-15=0

    • 2 years ago
  15. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh my God.. Sorry, I was thinking that, that was your post.. Really sorry..

    • 2 years ago
  16. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    That was of Nurali..

    • 2 years ago
  17. hba Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yeah lol :D Thanks anyway :)

    • 2 years ago
  18. waterineyes Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes you are right..

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.