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  • hba

Equation of a circle with ends of diameter at (-3,2) and (5,-6) is :

Mathematics
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  • hba
@hartnn @waterineyes I have no clue about this one........
that is simple.
mid-point is centre

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Other answers:

Find the distance between and divide it by 2 to find radius..
distance between the two points = diameter =2r
Do you know how to find midpoint or not??
  • hba
I know nothing lol but i am going to give you a tutorial on Conic section soon promise :D
  • hba
@waterineyes noooooooo
u don't know how to find mid-point ? thats news... just take the average of co-ordinates.
  • hba
x+y/2 but x1 or x2
for x-coordinate of midpoint, u take average of x-coordinates of endpoints
(-3+5)/2
Sorry net stopped working..
And I think your mind too.. @hba
\[Midpoint(x,y) = (\frac{x_1 +x_2}{2}, \frac{y_1+y_2}{2})\]
  • hba
@waterineyes Yeah right lol and [Math processing error ] Anyways @hartnn I remember (x,y)=(x1+x2/2,y1+y2/2)
  • hba
@waterineyes I cannot see latex
so whats the midpoint ? centre
  • hba
(x,y)=(1,-2)
thats correct centre
now find radius
Just refresh your page then..
  • hba
So i use the old radius formula ?
  • hba
\[r=\sqrt{g^2+f^2-c}\]
  • hba
@waterineyes @hartnn Do you have a better way ?
not that, can u find distance between two points ?
What are you doing man?? Use distance formula..
  • hba
Yeah
Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)
\[Distance = \sqrt{(x_2-x_1)^2 - (y_2-y_1)^2}\]
  • hba
\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
  • hba
lol
Written three times but used not atleast once.. ha ha ha..
lol :P
  • hba
\[d=8\sqrt{2}\]
  • hba
what next ?
radius = d/2
  • hba
commented
This you have got is length of Diameter.. You have to find radius so you will half it..
  • hba
r=4root(2)
yup... u know what to do from now....
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  • hba
(x-a)^2+(y-b)^2=r^2
Yep Go Ahead..
  • hba
x^2+y^2-2x+4y-27=0
Yep..
1 + 4 = 32 implies -27 on LHS..
  • hba
Thanks a lot @hartnn and @waterineyes
You are welcome dear..

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