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hba

  • 3 years ago

Equation of a circle with ends of diameter at (-3,2) and (5,-6) is :

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  1. hba
    • 3 years ago
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    @hartnn @waterineyes I have no clue about this one........

  2. hartnn
    • 3 years ago
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    that is simple.

  3. hartnn
    • 3 years ago
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    mid-point is centre

  4. waterineyes
    • 3 years ago
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    Find the distance between and divide it by 2 to find radius..

  5. hartnn
    • 3 years ago
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    distance between the two points = diameter =2r

  6. waterineyes
    • 3 years ago
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    Do you know how to find midpoint or not??

  7. hba
    • 3 years ago
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    I know nothing lol but i am going to give you a tutorial on Conic section soon promise :D

  8. hba
    • 3 years ago
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    @waterineyes noooooooo

  9. hartnn
    • 3 years ago
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    u don't know how to find mid-point ? thats news... just take the average of co-ordinates.

  10. hba
    • 3 years ago
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    x+y/2 but x1 or x2

  11. hartnn
    • 3 years ago
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    for x-coordinate of midpoint, u take average of x-coordinates of endpoints

  12. hartnn
    • 3 years ago
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    (-3+5)/2

  13. waterineyes
    • 3 years ago
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    Sorry net stopped working..

  14. waterineyes
    • 3 years ago
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    And I think your mind too.. @hba

  15. waterineyes
    • 3 years ago
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    \[Midpoint(x,y) = (\frac{x_1 +x_2}{2}, \frac{y_1+y_2}{2})\]

  16. hba
    • 3 years ago
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    @waterineyes Yeah right lol and [Math processing error ] Anyways @hartnn I remember (x,y)=(x1+x2/2,y1+y2/2)

  17. hba
    • 3 years ago
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    @waterineyes I cannot see latex

  18. hartnn
    • 3 years ago
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    so whats the midpoint ? centre

  19. hba
    • 3 years ago
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    (x,y)=(1,-2)

  20. hartnn
    • 3 years ago
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    thats correct centre

  21. hartnn
    • 3 years ago
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    now find radius

  22. waterineyes
    • 3 years ago
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    Just refresh your page then..

  23. hba
    • 3 years ago
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    So i use the old radius formula ?

  24. hba
    • 3 years ago
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    \[r=\sqrt{g^2+f^2-c}\]

  25. hba
    • 3 years ago
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    @waterineyes @hartnn Do you have a better way ?

  26. hartnn
    • 3 years ago
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    not that, can u find distance between two points ?

  27. waterineyes
    • 3 years ago
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    What are you doing man?? Use distance formula..

  28. hba
    • 3 years ago
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    Yeah

  29. hartnn
    • 3 years ago
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    Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\)

  30. waterineyes
    • 3 years ago
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    \[Distance = \sqrt{(x_2-x_1)^2 - (y_2-y_1)^2}\]

  31. hba
    • 3 years ago
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    \[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]

  32. hba
    • 3 years ago
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    lol

  33. waterineyes
    • 3 years ago
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    Written three times but used not atleast once.. ha ha ha..

  34. hartnn
    • 3 years ago
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    lol :P

  35. hba
    • 3 years ago
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    \[d=8\sqrt{2}\]

  36. hba
    • 3 years ago
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    what next ?

  37. hartnn
    • 3 years ago
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    radius = d/2

  38. hba
    • 3 years ago
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    @hartnn ?

  39. hartnn
    • 3 years ago
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    commented

  40. waterineyes
    • 3 years ago
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    This you have got is length of Diameter.. You have to find radius so you will half it..

  41. hba
    • 3 years ago
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    r=4root(2)

  42. hartnn
    • 3 years ago
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    yup... u know what to do from now....

  43. waterineyes
    • 3 years ago
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    |dw:1353175013593:dw|

  44. hba
    • 3 years ago
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    (x-a)^2+(y-b)^2=r^2

  45. waterineyes
    • 3 years ago
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    Yep Go Ahead..

  46. hba
    • 3 years ago
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    x^2+y^2-2x+4y-27=0

  47. waterineyes
    • 3 years ago
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    Yep..

  48. waterineyes
    • 3 years ago
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    1 + 4 = 32 implies -27 on LHS..

  49. hba
    • 3 years ago
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    Thanks a lot @hartnn and @waterineyes

  50. waterineyes
    • 3 years ago
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    You are welcome dear..

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