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hba
Group Title
Equation of a circle with ends of diameter at (3,2) and (5,6) is :
 one year ago
 one year ago
hba Group Title
Equation of a circle with ends of diameter at (3,2) and (5,6) is :
 one year ago
 one year ago

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hba Group TitleBest ResponseYou've already chosen the best response.0
@hartnn @waterineyes I have no clue about this one........
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
that is simple.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
midpoint is centre
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Find the distance between and divide it by 2 to find radius..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
distance between the two points = diameter =2r
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Do you know how to find midpoint or not??
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
I know nothing lol but i am going to give you a tutorial on Conic section soon promise :D
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes noooooooo
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
u don't know how to find midpoint ? thats news... just take the average of coordinates.
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
x+y/2 but x1 or x2
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
for xcoordinate of midpoint, u take average of xcoordinates of endpoints
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Sorry net stopped working..
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
And I think your mind too.. @hba
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
\[Midpoint(x,y) = (\frac{x_1 +x_2}{2}, \frac{y_1+y_2}{2})\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes Yeah right lol and [Math processing error ] Anyways @hartnn I remember (x,y)=(x1+x2/2,y1+y2/2)
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes I cannot see latex
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
so whats the midpoint ? centre
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
thats correct centre
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
now find radius
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Just refresh your page then..
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
So i use the old radius formula ?
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
\[r=\sqrt{g^2+f^2c}\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
@waterineyes @hartnn Do you have a better way ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
not that, can u find distance between two points ?
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
What are you doing man?? Use distance formula..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1x_2)^2+(y_1y_2)^2}\)
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
\[Distance = \sqrt{(x_2x_1)^2  (y_2y_1)^2}\]
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
\[d=\sqrt{(x2x1)^2+(y2y1)^2}\]
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Written three times but used not atleast once.. ha ha ha..
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
\[d=8\sqrt{2}\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
radius = d/2
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
This you have got is length of Diameter.. You have to find radius so you will half it..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yup... u know what to do from now....
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
dw:1353175013593:dw
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
(xa)^2+(yb)^2=r^2
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
Yep Go Ahead..
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
x^2+y^22x+4y27=0
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
1 + 4 = 32 implies 27 on LHS..
 one year ago

hba Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot @hartnn and @waterineyes
 one year ago

waterineyes Group TitleBest ResponseYou've already chosen the best response.2
You are welcome dear..
 one year ago
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