A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
The center of the circle with eqn.
4x^2+4y^28x+12y25=0 is
I am just conforming my answer...........
 2 years ago
The center of the circle with eqn. 4x^2+4y^28x+12y25=0 is I am just conforming my answer...........

This Question is Closed

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0No, I won't tell you..

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0posting a question means asking....

hba
 2 years ago
Best ResponseYou've already chosen the best response.1Please see the ques carefully

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Where is the answer you want to confirm??

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0If you have solved, then please put your answer in the question box..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0It is looking bad to me..

hba
 2 years ago
Best ResponseYou've already chosen the best response.1That means it is absolutely right :D

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0If you think so then yes..

hba
 2 years ago
Best ResponseYou've already chosen the best response.1radius of the circle with the eqn, x^2+y^2+12x10y=0 is I got \[\sqrt{61}\]

hba
 2 years ago
Best ResponseYou've already chosen the best response.1@waterineyes Right or wrong ?

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Yes you are right..

waterineyes
 2 years ago
Best ResponseYou've already chosen the best response.0Yes you are right radius is root(61)..
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.