hba
The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:



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waterineyes
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Just analyze your problem..

waterineyes
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x and y axes are tangent of your given circle and it is having radius as "a"..

hba
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dw:1353177176620:dw

hartnn
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from that u can find center..

waterineyes
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dw:1353177255765:dw

waterineyes
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Circle is touching y axis too @hba

waterineyes
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dw:1353177331464:dw

hba
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Now My mind stopped working :(

waterineyes
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Radius is "a" you are given, so keep it as such..

waterineyes
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I am marking the distance, you will tell me what is it??
dw:1353177450919:dw

hba
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r=a ok

hba
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So x=y

hba
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@waterineyes :(

waterineyes
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I am just saying that, tell me what will be the distances that I have marked??

hba
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(g,f)=(a,a)

waterineyes
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Now, you have got..

hba
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@waterineyes @hartnn Please help

waterineyes
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This is your center and you have radius as a..

waterineyes
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Now, just use the equation of center.

hba
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Thank you for confusing me and helping me at the same time
x^2+y^22ax2ay+a^2=0

waterineyes
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No..

hba
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Then ?

waterineyes
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Ha ha ha..
Just confusing you more..
It looks bad to me..

hba
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Thank yewwww

waterineyes
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You are welcome dear..