• hba

The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:

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  • hba

The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:

Mathematics
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Just analyze your problem..
x and y axes are tangent of your given circle and it is having radius as "a"..
  • hba
|dw:1353177176620:dw|

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Other answers:

from that u can find center..
|dw:1353177255765:dw|
Circle is touching y axis too @hba
|dw:1353177331464:dw|
  • hba
Now My mind stopped working :(
Radius is "a" you are given, so keep it as such..
I am marking the distance, you will tell me what is it?? |dw:1353177450919:dw|
  • hba
r=a ok
  • hba
So x=y
  • hba
I am just saying that, tell me what will be the distances that I have marked??
  • hba
(g,f)=(a,a)
Now, you have got..
  • hba
@waterineyes @hartnn Please help
This is your center and you have radius as a..
Now, just use the equation of center.
  • hba
Thank you for confusing me and helping me at the same time x^2+y^2-2ax-2ay+a^2=0
No..
  • hba
Then ?
Ha ha ha.. Just confusing you more.. It looks bad to me..
  • hba
Thank yewwww
You are welcome dear..

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