hba 3 years ago The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:

1. waterineyes

2. waterineyes

x and y axes are tangent of your given circle and it is having radius as "a"..

3. hba

|dw:1353177176620:dw|

4. hartnn

from that u can find center..

5. waterineyes

|dw:1353177255765:dw|

6. waterineyes

Circle is touching y axis too @hba

7. waterineyes

|dw:1353177331464:dw|

8. hba

Now My mind stopped working :(

9. waterineyes

Radius is "a" you are given, so keep it as such..

10. waterineyes

I am marking the distance, you will tell me what is it?? |dw:1353177450919:dw|

11. hba

r=a ok

12. hba

So x=y

13. hba

@waterineyes :(

14. waterineyes

I am just saying that, tell me what will be the distances that I have marked??

15. hba

(g,f)=(a,a)

16. waterineyes

Now, you have got..

17. hba

18. waterineyes

19. waterineyes

Now, just use the equation of center.

20. hba

Thank you for confusing me and helping me at the same time x^2+y^2-2ax-2ay+a^2=0

21. waterineyes

No..

22. hba

Then ?

23. waterineyes

Ha ha ha.. Just confusing you more.. It looks bad to me..

24. hba

Thank yewwww

25. waterineyes

You are welcome dear..