hba
  • hba
The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Just analyze your problem..
anonymous
  • anonymous
x and y axes are tangent of your given circle and it is having radius as "a"..
hba
  • hba
|dw:1353177176620:dw|

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hartnn
  • hartnn
from that u can find center..
anonymous
  • anonymous
|dw:1353177255765:dw|
anonymous
  • anonymous
Circle is touching y axis too @hba
anonymous
  • anonymous
|dw:1353177331464:dw|
hba
  • hba
Now My mind stopped working :(
anonymous
  • anonymous
Radius is "a" you are given, so keep it as such..
anonymous
  • anonymous
I am marking the distance, you will tell me what is it?? |dw:1353177450919:dw|
hba
  • hba
r=a ok
hba
  • hba
So x=y
hba
  • hba
@waterineyes :(
anonymous
  • anonymous
I am just saying that, tell me what will be the distances that I have marked??
hba
  • hba
(g,f)=(a,a)
anonymous
  • anonymous
Now, you have got..
hba
  • hba
@waterineyes @hartnn Please help
anonymous
  • anonymous
This is your center and you have radius as a..
anonymous
  • anonymous
Now, just use the equation of center.
hba
  • hba
Thank you for confusing me and helping me at the same time x^2+y^2-2ax-2ay+a^2=0
anonymous
  • anonymous
No..
hba
  • hba
Then ?
anonymous
  • anonymous
Ha ha ha.. Just confusing you more.. It looks bad to me..
hba
  • hba
Thank yewwww
anonymous
  • anonymous
You are welcome dear..

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