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hba

The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:

  • one year ago
  • one year ago

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  1. waterineyes
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    Just analyze your problem..

    • one year ago
  2. waterineyes
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    x and y axes are tangent of your given circle and it is having radius as "a"..

    • one year ago
  3. hba
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    |dw:1353177176620:dw|

    • one year ago
  4. hartnn
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    from that u can find center..

    • one year ago
  5. waterineyes
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    |dw:1353177255765:dw|

    • one year ago
  6. waterineyes
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    Circle is touching y axis too @hba

    • one year ago
  7. waterineyes
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    |dw:1353177331464:dw|

    • one year ago
  8. hba
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    Now My mind stopped working :(

    • one year ago
  9. waterineyes
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    Radius is "a" you are given, so keep it as such..

    • one year ago
  10. waterineyes
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    I am marking the distance, you will tell me what is it?? |dw:1353177450919:dw|

    • one year ago
  11. hba
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    r=a ok

    • one year ago
  12. hba
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    So x=y

    • one year ago
  13. hba
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    @waterineyes :(

    • one year ago
  14. waterineyes
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    I am just saying that, tell me what will be the distances that I have marked??

    • one year ago
  15. hba
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    (g,f)=(a,a)

    • one year ago
  16. waterineyes
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    Now, you have got..

    • one year ago
  17. hba
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    @waterineyes @hartnn Please help

    • one year ago
  18. waterineyes
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    This is your center and you have radius as a..

    • one year ago
  19. waterineyes
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    Now, just use the equation of center.

    • one year ago
  20. hba
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    Thank you for confusing me and helping me at the same time x^2+y^2-2ax-2ay+a^2=0

    • one year ago
  21. waterineyes
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    No..

    • one year ago
  22. hba
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    Then ?

    • one year ago
  23. waterineyes
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    Ha ha ha.. Just confusing you more.. It looks bad to me..

    • one year ago
  24. hba
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    Thank yewwww

    • one year ago
  25. waterineyes
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    You are welcome dear..

    • one year ago
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