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hba

  • 3 years ago

The equation of a circle of radius 'a' and lying in the second quadrant such that it is tangent to both the axes,is:

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  1. waterineyes
    • 3 years ago
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    Just analyze your problem..

  2. waterineyes
    • 3 years ago
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    x and y axes are tangent of your given circle and it is having radius as "a"..

  3. hba
    • 3 years ago
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    |dw:1353177176620:dw|

  4. hartnn
    • 3 years ago
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    from that u can find center..

  5. waterineyes
    • 3 years ago
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    |dw:1353177255765:dw|

  6. waterineyes
    • 3 years ago
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    Circle is touching y axis too @hba

  7. waterineyes
    • 3 years ago
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    |dw:1353177331464:dw|

  8. hba
    • 3 years ago
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    Now My mind stopped working :(

  9. waterineyes
    • 3 years ago
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    Radius is "a" you are given, so keep it as such..

  10. waterineyes
    • 3 years ago
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    I am marking the distance, you will tell me what is it?? |dw:1353177450919:dw|

  11. hba
    • 3 years ago
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    r=a ok

  12. hba
    • 3 years ago
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    So x=y

  13. hba
    • 3 years ago
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    @waterineyes :(

  14. waterineyes
    • 3 years ago
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    I am just saying that, tell me what will be the distances that I have marked??

  15. hba
    • 3 years ago
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    (g,f)=(a,a)

  16. waterineyes
    • 3 years ago
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    Now, you have got..

  17. hba
    • 3 years ago
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    @waterineyes @hartnn Please help

  18. waterineyes
    • 3 years ago
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    This is your center and you have radius as a..

  19. waterineyes
    • 3 years ago
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    Now, just use the equation of center.

  20. hba
    • 3 years ago
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    Thank you for confusing me and helping me at the same time x^2+y^2-2ax-2ay+a^2=0

  21. waterineyes
    • 3 years ago
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    No..

  22. hba
    • 3 years ago
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    Then ?

  23. waterineyes
    • 3 years ago
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    Ha ha ha.. Just confusing you more.. It looks bad to me..

  24. hba
    • 3 years ago
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    Thank yewwww

  25. waterineyes
    • 3 years ago
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    You are welcome dear..

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