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hartnnBest ResponseYou've already chosen the best response.0
subtract 7 from both sides
 one year ago

dragonslyBest ResponseYou've already chosen the best response.0
dw:1353177800615:dw
 one year ago

anas2000Best ResponseYou've already chosen the best response.1
First square (x3). You will need to FOIL this. (x3)(x3) = x^23x3x+9 = x^26x+9 Then, multiply by 2. 23 = 2(x^26x+9)+7 = (2x^212x+18)+7 Add 7 to 18. 23 = 2x^212x+25 Then subtract 23 on both sides. 0 = 2x^212x+2 The right side all have the common factor of 2, so divide both sides by 2. 0 = x^26x+1 If you try to factor the equation, you'll notice that it won't work, so you'll need to use the quadratic equation. b ± √(b^2  4ac) / 2a x^2 (1) = a 6x (6) = b 1 = c Plug in the numbers. 6± √[(6)^2  4(1)(1)] / 2(1) 6± √(364) / 2 6± √32 / 2 Simplify. 6± √16*2 / 2 6± 4√2 / 2 = 3± 2√2
 one year ago

evy15Best ResponseYou've already chosen the best response.0
ok I see, thanks everyone!! (:
 one year ago
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