A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
what are the solutions of 23=2(x3)^2+7?
please help?
anonymous
 3 years ago
what are the solutions of 23=2(x3)^2+7? please help?

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0subtract 7 from both sides

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1353177800615:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0First square (x3). You will need to FOIL this. (x3)(x3) = x^23x3x+9 = x^26x+9 Then, multiply by 2. 23 = 2(x^26x+9)+7 = (2x^212x+18)+7 Add 7 to 18. 23 = 2x^212x+25 Then subtract 23 on both sides. 0 = 2x^212x+2 The right side all have the common factor of 2, so divide both sides by 2. 0 = x^26x+1 If you try to factor the equation, you'll notice that it won't work, so you'll need to use the quadratic equation. b ± √(b^2  4ac) / 2a x^2 (1) = a 6x (6) = b 1 = c Plug in the numbers. 6± √[(6)^2  4(1)(1)] / 2(1) 6± √(364) / 2 6± √32 / 2 Simplify. 6± √16*2 / 2 6± 4√2 / 2 = 3± 2√2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok I see, thanks everyone!! (:
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.