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anonymous
 4 years ago
what are the solutions of 23=2(x3)^2+7?
please help?
anonymous
 4 years ago
what are the solutions of 23=2(x3)^2+7? please help?

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hartnn
 4 years ago
Best ResponseYou've already chosen the best response.0subtract 7 from both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1353177800615:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0First square (x3). You will need to FOIL this. (x3)(x3) = x^23x3x+9 = x^26x+9 Then, multiply by 2. 23 = 2(x^26x+9)+7 = (2x^212x+18)+7 Add 7 to 18. 23 = 2x^212x+25 Then subtract 23 on both sides. 0 = 2x^212x+2 The right side all have the common factor of 2, so divide both sides by 2. 0 = x^26x+1 If you try to factor the equation, you'll notice that it won't work, so you'll need to use the quadratic equation. b ± √(b^2  4ac) / 2a x^2 (1) = a 6x (6) = b 1 = c Plug in the numbers. 6± √[(6)^2  4(1)(1)] / 2(1) 6± √(364) / 2 6± √32 / 2 Simplify. 6± √16*2 / 2 6± 4√2 / 2 = 3± 2√2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok I see, thanks everyone!! (:
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