## arlira 3 years ago Help me PLEASE I'm confused!!! The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.

1. hartnn

at which step are u confused ?

Shorter leg = x longer leg = x+7 hypotenuse = x+7+1 = x+8 Do you know how to proceed now ?

3. arlira

no I don't know-how to continue

4. arlira

hartnn i dont know how to figure out what belongs to what leg

5. hartnn

did u get @Aditi_Singh 's explanation ?

6. arlira

nope

7. elisichi

I'm guessing that x is the length of the longer leg, and that this can be written as: \[X^2+ (X-7)^2 = X+1 \] Then, you can solve from there by expanding brackets and you get a quadratic equation: \[x^2 -8x+48=0\]

Almost Correct , but x^2 + (x+7)^2 = (x+8)^2 Apply Pythagoras theorem!

9. elisichi

Wait no.. my answer makes sense. Doesnt it? \[x^2+(x−7)^2=(x+1)^2 \] \[= x^2+x^2-7x+49=x^2 + x+1 \] \[x^2-8x+48=0 \]

:| , ofcourse it does makes sense. But here, your hypotenuse isn't (x+1) , it is x+8 ..

11. elisichi

Im taking x as the longer leg, not the shorter one

Okay, then the longer leg would be x , shorter length would be x-7, and hyp would be x+1 .. Well done buddy :D , you were absolutely correct :D

13. elisichi

Woohoo ;) High five for being right :D