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- anonymous

Help me PLEASE I'm confused!!!
The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.

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- anonymous

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- hartnn

at which step are u confused ?

- anonymous

Shorter leg = x
longer leg = x+7
hypotenuse = x+7+1 = x+8
Do you know how to proceed now ?

- anonymous

no I don't know-how to continue

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- anonymous

hartnn i dont know how to figure out what belongs to what leg

- hartnn

did u get @Aditi_Singh 's explanation ?

- anonymous

nope

- anonymous

I'm guessing that x is the length of the longer leg, and that this can be written as:
\[X^2+ (X-7)^2 = X+1 \]
Then, you can solve from there by expanding brackets and you get a quadratic equation:
\[x^2 -8x+48=0\]

- anonymous

Almost Correct , but x^2 + (x+7)^2 = (x+8)^2
Apply Pythagoras theorem!

- anonymous

Wait no.. my answer makes sense. Doesnt it?
\[x^2+(x−7)^2=(x+1)^2 \]
\[= x^2+x^2-7x+49=x^2 + x+1 \]
\[x^2-8x+48=0 \]

- anonymous

:| , ofcourse it does makes sense. But here, your hypotenuse isn't (x+1) , it is x+8 ..

- anonymous

Im taking x as the longer leg, not the shorter one

- anonymous

Okay, then the longer leg would be x , shorter length would be x-7, and hyp would be x+1 .. Well done buddy :D , you were absolutely correct :D

- anonymous

Woohoo ;) High five for being right :D

- anonymous

High five ;) :D

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