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arlira Group Title

Help me PLEASE I'm confused!!! The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.

  • one year ago
  • one year ago

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  1. hartnn Group Title
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    at which step are u confused ?

    • one year ago
  2. Aditi_Singh Group Title
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    Shorter leg = x longer leg = x+7 hypotenuse = x+7+1 = x+8 Do you know how to proceed now ?

    • one year ago
  3. arlira Group Title
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    no I don't know-how to continue

    • one year ago
  4. arlira Group Title
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    hartnn i dont know how to figure out what belongs to what leg

    • one year ago
  5. hartnn Group Title
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    did u get @Aditi_Singh 's explanation ?

    • one year ago
  6. arlira Group Title
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    nope

    • one year ago
  7. elisichi Group Title
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    I'm guessing that x is the length of the longer leg, and that this can be written as: \[X^2+ (X-7)^2 = X+1 \] Then, you can solve from there by expanding brackets and you get a quadratic equation: \[x^2 -8x+48=0\]

    • one year ago
  8. Aditi_Singh Group Title
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    Almost Correct , but x^2 + (x+7)^2 = (x+8)^2 Apply Pythagoras theorem!

    • one year ago
  9. elisichi Group Title
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    Wait no.. my answer makes sense. Doesnt it? \[x^2+(x−7)^2=(x+1)^2 \] \[= x^2+x^2-7x+49=x^2 + x+1 \] \[x^2-8x+48=0 \]

    • one year ago
  10. Aditi_Singh Group Title
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    :| , ofcourse it does makes sense. But here, your hypotenuse isn't (x+1) , it is x+8 ..

    • one year ago
  11. elisichi Group Title
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    Im taking x as the longer leg, not the shorter one

    • one year ago
  12. Aditi_Singh Group Title
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    Okay, then the longer leg would be x , shorter length would be x-7, and hyp would be x+1 .. Well done buddy :D , you were absolutely correct :D

    • one year ago
  13. elisichi Group Title
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    Woohoo ;) High five for being right :D

    • one year ago
  14. Aditi_Singh Group Title
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    High five ;) :D

    • one year ago
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