anonymous
  • anonymous
Help me PLEASE I'm confused!!! The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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hartnn
  • hartnn
at which step are u confused ?
anonymous
  • anonymous
Shorter leg = x longer leg = x+7 hypotenuse = x+7+1 = x+8 Do you know how to proceed now ?
anonymous
  • anonymous
no I don't know-how to continue

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anonymous
  • anonymous
hartnn i dont know how to figure out what belongs to what leg
hartnn
  • hartnn
did u get @Aditi_Singh 's explanation ?
anonymous
  • anonymous
nope
anonymous
  • anonymous
I'm guessing that x is the length of the longer leg, and that this can be written as: \[X^2+ (X-7)^2 = X+1 \] Then, you can solve from there by expanding brackets and you get a quadratic equation: \[x^2 -8x+48=0\]
anonymous
  • anonymous
Almost Correct , but x^2 + (x+7)^2 = (x+8)^2 Apply Pythagoras theorem!
anonymous
  • anonymous
Wait no.. my answer makes sense. Doesnt it? \[x^2+(x−7)^2=(x+1)^2 \] \[= x^2+x^2-7x+49=x^2 + x+1 \] \[x^2-8x+48=0 \]
anonymous
  • anonymous
:| , ofcourse it does makes sense. But here, your hypotenuse isn't (x+1) , it is x+8 ..
anonymous
  • anonymous
Im taking x as the longer leg, not the shorter one
anonymous
  • anonymous
Okay, then the longer leg would be x , shorter length would be x-7, and hyp would be x+1 .. Well done buddy :D , you were absolutely correct :D
anonymous
  • anonymous
Woohoo ;) High five for being right :D
anonymous
  • anonymous
High five ;) :D

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