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arlira
Group Title
Help me PLEASE I'm confused!!!
The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.
 one year ago
 one year ago
arlira Group Title
Help me PLEASE I'm confused!!! The hypotenuse of a right triangle is 1cm longer than the longer leg. The shorter leg is 7cm shorter than the longer leg. Find the length of the longer leg of the right triangle.Label each side of the triangle. Then substitute into Pythagorean Theorem.
 one year ago
 one year ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.0
at which step are u confused ?
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.2
Shorter leg = x longer leg = x+7 hypotenuse = x+7+1 = x+8 Do you know how to proceed now ?
 one year ago

arlira Group TitleBest ResponseYou've already chosen the best response.0
no I don't knowhow to continue
 one year ago

arlira Group TitleBest ResponseYou've already chosen the best response.0
hartnn i dont know how to figure out what belongs to what leg
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
did u get @Aditi_Singh 's explanation ?
 one year ago

elisichi Group TitleBest ResponseYou've already chosen the best response.1
I'm guessing that x is the length of the longer leg, and that this can be written as: \[X^2+ (X7)^2 = X+1 \] Then, you can solve from there by expanding brackets and you get a quadratic equation: \[x^2 8x+48=0\]
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.2
Almost Correct , but x^2 + (x+7)^2 = (x+8)^2 Apply Pythagoras theorem!
 one year ago

elisichi Group TitleBest ResponseYou've already chosen the best response.1
Wait no.. my answer makes sense. Doesnt it? \[x^2+(x−7)^2=(x+1)^2 \] \[= x^2+x^27x+49=x^2 + x+1 \] \[x^28x+48=0 \]
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.2
: , ofcourse it does makes sense. But here, your hypotenuse isn't (x+1) , it is x+8 ..
 one year ago

elisichi Group TitleBest ResponseYou've already chosen the best response.1
Im taking x as the longer leg, not the shorter one
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.2
Okay, then the longer leg would be x , shorter length would be x7, and hyp would be x+1 .. Well done buddy :D , you were absolutely correct :D
 one year ago

elisichi Group TitleBest ResponseYou've already chosen the best response.1
Woohoo ;) High five for being right :D
 one year ago

Aditi_Singh Group TitleBest ResponseYou've already chosen the best response.2
High five ;) :D
 one year ago
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