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hba

If the radius of a circle is increased by 10 % then the area is increased by,

  • one year ago
  • one year ago

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  1. tkhunny
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    \(\pi r^2\) \(\pi (r*1.1)^{2} = 1.21\cdot\pi r^{2}\) What do you think?

    • one year ago
  2. hba
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    @hartnn Yeah lol ? It is a circle but it is a very diff ques..

    • one year ago
  3. hba
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    @tkhunny You are welcome to provide hints and explain

    • one year ago
  4. tkhunny
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    Already did. Radius increased by 10% -- r*1.1 Area is increased by ???

    • one year ago
  5. hba
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    Please explain how did you do the first step

    • one year ago
  6. tkhunny
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    Area of a Circle = \(\pi r^{2}\), given the radius. That's the first step.

    • one year ago
  7. hba
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    I know that the Area of a circle = pi r^2

    • one year ago
  8. tkhunny
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    New Radius is 10% greater than old radius. R = r*1.1 Area of new circle: \(\pi R^{2}\).

    • one year ago
  9. hba
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    Got it what next ?

    • one year ago
  10. tkhunny
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    Raio of New Area to Old Area \(\dfrac{\pi R^{2}}{\pi r^{2}}\).

    • one year ago
  11. hba
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    Ratio*

    • one year ago
  12. tkhunny
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    *Ratio - right A little algebra \(\dfrac{\pi R^{2}}{\pi r^{2}} = \dfrac{R^{2}}{r^{2}} = \dfrac{(1.1\cdot r)^{2}}{r^{2}} = \dfrac{1.1^{2}r^{2}}{r^{2}} = 1.1^{2} = 1.21\) And we see a 21% increase!

    • one year ago
  13. hba
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    Thank you.

    • one year ago
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