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hba

  • 3 years ago

If the radius of a circle is increased by 10 % then the area is increased by,

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  1. tkhunny
    • 3 years ago
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    \(\pi r^2\) \(\pi (r*1.1)^{2} = 1.21\cdot\pi r^{2}\) What do you think?

  2. hba
    • 3 years ago
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    @hartnn Yeah lol ? It is a circle but it is a very diff ques..

  3. hba
    • 3 years ago
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    @tkhunny You are welcome to provide hints and explain

  4. tkhunny
    • 3 years ago
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    Already did. Radius increased by 10% -- r*1.1 Area is increased by ???

  5. hba
    • 3 years ago
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    Please explain how did you do the first step

  6. tkhunny
    • 3 years ago
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    Area of a Circle = \(\pi r^{2}\), given the radius. That's the first step.

  7. hba
    • 3 years ago
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    I know that the Area of a circle = pi r^2

  8. tkhunny
    • 3 years ago
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    New Radius is 10% greater than old radius. R = r*1.1 Area of new circle: \(\pi R^{2}\).

  9. hba
    • 3 years ago
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    Got it what next ?

  10. tkhunny
    • 3 years ago
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    Raio of New Area to Old Area \(\dfrac{\pi R^{2}}{\pi r^{2}}\).

  11. hba
    • 3 years ago
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    Ratio*

  12. tkhunny
    • 3 years ago
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    *Ratio - right A little algebra \(\dfrac{\pi R^{2}}{\pi r^{2}} = \dfrac{R^{2}}{r^{2}} = \dfrac{(1.1\cdot r)^{2}}{r^{2}} = \dfrac{1.1^{2}r^{2}}{r^{2}} = 1.1^{2} = 1.21\) And we see a 21% increase!

  13. hba
    • 3 years ago
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    Thank you.

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