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chels1226
 2 years ago
Best ResponseYou've already chosen the best response.1A. x=0, 2 B. x=0,2,2 C.x=2,2 D.x=0

nincompoop
 2 years ago
Best ResponseYou've already chosen the best response.1Solve for x over the real numbers: 2/(x+2) = (x+4)/(x^24) Multiply both sides by a polynomial to clear fractions. Cross multiply: 2 (x^24) = (x+2) (x+4) Write the quadratic polynomial on the left hand side in standard form. Expand out terms of the left hand side: 82 x^2 = (x+2) (x+4) Write the quadratic polynomial on the right hand side in standard form. Expand out terms of the right hand side: 82 x^2 = x^2+6 x+8 Move everything to the left hand side. Subtract x^2+6 x+8 from both sides: 6 x3 x^2 = 0 Factor the left hand side. Factor x and constant terms from the left hand side: 3 x (x+2) = 0 Divide both sides by a constant to simplify the equation. Divide both sides by 3: x (x+2) = 0 Solve each term in the product separately. Split into two equations: x = 0 or x+2 = 0 Look at the second equation: Solve for x. Subtract 2 from both sides: x = 0 or x = 2 Now test that these solutions are correct by substituting into the original equation. Check the solution x = 2. 2/(x+2) => 2/(22) = infinity^~ ~~ infinity^~ (x+4)/(x^24) => (42)/(44) = infinity^~ ~~ infinity^~: So this solution is incorrect Check the solution x = 0. 2/(x+2) => 2/(2+0) = 1 (x+4)/(x^24) => (4+0)/(04) = 1: So this solution is correct Gather any correct solutions. The solution is: Answer: x = 0

graydarl
 2 years ago
Best ResponseYou've already chosen the best response.0(x+2)*(x+4)=(x^24)*(2) x^2+4x+2x+8=2x^2+8 3x^2+6x=0 delta=6^24*3*0=36 x1,2=[6+sqrt(delta)]/6 so x1=0 and x2=2 so A is the correct answer
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