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chrislb22

  • 3 years ago

can someone help me please? Find the derivative of the function s(x) = square root x + 3/square root x

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  1. chrislb22
    • 3 years ago
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    \[\sqrt{x} + 3/\sqrt{x}\]

  2. anonymous
    • 3 years ago
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    you should memorize the derivative of \(\sqrt{x}\) because it is a very common function the derivative of \(\sqrt{x}\) is \(\frac{1}{2\sqrt{x}}\)

  3. anonymous
    • 3 years ago
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    as for \(\frac{3}{\sqrt{x}}\) you can rewrite it as \(3x^{-\frac{1}{2}}\) and use the power rule

  4. chrislb22
    • 3 years ago
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    \[1/2\sqrt{x} - 3x^-1/2\]

  5. chrislb22
    • 3 years ago
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    is that correct ?^^^

  6. anonymous
    • 3 years ago
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    no

  7. anonymous
    • 3 years ago
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    the first part is right, you still have to take the derivative of \[3x^{-\frac{1}{2}}\] using the power rule

  8. anonymous
    • 3 years ago
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    i just rewrote it in exponential form, you still have to find the derivative

  9. chrislb22
    • 3 years ago
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    so -3/2x-1?

  10. chrislb22
    • 3 years ago
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    \[\frac{ -3 }{ 2 }x^1\]

  11. chrislb22
    • 3 years ago
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    @satellite73

  12. chrislb22
    • 3 years ago
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    @satellite73 \[\frac{ 1 }{ 2 }\sqrt{x}+ -3/2x ^{-1}\]

  13. chrislb22
    • 3 years ago
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    is that correct?

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