A community for students.
Here's the question you clicked on:
 0 viewing
chrislb22
 3 years ago
can someone help me please?
Find the derivative of the function
s(x) = square root x + 3/square root x
chrislb22
 3 years ago
can someone help me please? Find the derivative of the function s(x) = square root x + 3/square root x

This Question is Closed

chrislb22
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x} + 3/\sqrt{x}\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1you should memorize the derivative of \(\sqrt{x}\) because it is a very common function the derivative of \(\sqrt{x}\) is \(\frac{1}{2\sqrt{x}}\)

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1as for \(\frac{3}{\sqrt{x}}\) you can rewrite it as \(3x^{\frac{1}{2}}\) and use the power rule

chrislb22
 3 years ago
Best ResponseYou've already chosen the best response.0\[1/2\sqrt{x}  3x^1/2\]

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1the first part is right, you still have to take the derivative of \[3x^{\frac{1}{2}}\] using the power rule

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.1i just rewrote it in exponential form, you still have to find the derivative

chrislb22
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3 }{ 2 }x^1\]

chrislb22
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 \[\frac{ 1 }{ 2 }\sqrt{x}+ 3/2x ^{1}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.