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burhan101 Group Title

How do i get rid of this fraction ?

  • 2 years ago
  • 2 years ago

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  1. burhan101 Group Title
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    \[\huge \frac{ (sinx-1)-(sinx+1) }{ (sinx+1)(six-1) }\]

    • 2 years ago
  2. ArkGoLucky Group Title
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    I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx-1)

    • 2 years ago
  3. burhan101 Group Title
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    oh so like multiplying by one right?

    • 2 years ago
  4. ArkGoLucky Group Title
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    yes

    • 2 years ago
  5. ArkGoLucky Group Title
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    but again I don't really know this stuff so maybe you should wait for more expert advice

    • 2 years ago
  6. burhan101 Group Title
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    okay, thanks :D

    • 2 years ago
  7. cwrw238 Group Title
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    you can simplify this denominator = sin^2 x - 1 = - cos^2 x numerator = -2 so we get -2 / - cos^2 x = 2 / cos^2 x = 2 sec^2 x fractions gone!

    • 2 years ago
  8. ArkGoLucky Group Title
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    okay I was off by a lot

    • 2 years ago
  9. burhan101 Group Title
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    |dw:1353193555599:dw| like this ? :S

    • 2 years ago
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