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burhan101

How do i get rid of this fraction ?

  • one year ago
  • one year ago

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  1. burhan101
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    \[\huge \frac{ (sinx-1)-(sinx+1) }{ (sinx+1)(six-1) }\]

    • one year ago
  2. ArkGoLucky
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    I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx-1)

    • one year ago
  3. burhan101
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    oh so like multiplying by one right?

    • one year ago
  4. ArkGoLucky
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    yes

    • one year ago
  5. ArkGoLucky
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    but again I don't really know this stuff so maybe you should wait for more expert advice

    • one year ago
  6. burhan101
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    okay, thanks :D

    • one year ago
  7. cwrw238
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    you can simplify this denominator = sin^2 x - 1 = - cos^2 x numerator = -2 so we get -2 / - cos^2 x = 2 / cos^2 x = 2 sec^2 x fractions gone!

    • one year ago
  8. ArkGoLucky
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    okay I was off by a lot

    • one year ago
  9. burhan101
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    |dw:1353193555599:dw| like this ? :S

    • one year ago
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