anonymous
  • anonymous
How do i get rid of this fraction ?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[\huge \frac{ (sinx-1)-(sinx+1) }{ (sinx+1)(six-1) }\]
anonymous
  • anonymous
I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx-1)
anonymous
  • anonymous
oh so like multiplying by one right?

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anonymous
  • anonymous
yes
anonymous
  • anonymous
but again I don't really know this stuff so maybe you should wait for more expert advice
anonymous
  • anonymous
okay, thanks :D
cwrw238
  • cwrw238
you can simplify this denominator = sin^2 x - 1 = - cos^2 x numerator = -2 so we get -2 / - cos^2 x = 2 / cos^2 x = 2 sec^2 x fractions gone!
anonymous
  • anonymous
okay I was off by a lot
anonymous
  • anonymous
|dw:1353193555599:dw| like this ? :S

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