burhan101
How do i get rid of this fraction ?



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burhan101
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\[\huge \frac{ (sinx1)(sinx+1) }{ (sinx+1)(six1) }\]

ArkGoLucky
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I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx1)

burhan101
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oh so like multiplying by one right?

ArkGoLucky
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yes

ArkGoLucky
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but again I don't really know this stuff so maybe you should wait for more expert advice

burhan101
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okay, thanks :D

cwrw238
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you can simplify this
denominator = sin^2 x  1 =  cos^2 x
numerator = 2
so we get 2 /  cos^2 x = 2 / cos^2 x = 2 sec^2 x
fractions gone!

ArkGoLucky
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okay I was off by a lot

burhan101
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dw:1353193555599:dw like this ? :S