## anonymous 3 years ago How do i get rid of this fraction ?

1. anonymous

$\huge \frac{ (sinx-1)-(sinx+1) }{ (sinx+1)(six-1) }$

2. anonymous

I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx-1)

3. anonymous

oh so like multiplying by one right?

4. anonymous

yes

5. anonymous

but again I don't really know this stuff so maybe you should wait for more expert advice

6. anonymous

okay, thanks :D

7. cwrw238

you can simplify this denominator = sin^2 x - 1 = - cos^2 x numerator = -2 so we get -2 / - cos^2 x = 2 / cos^2 x = 2 sec^2 x fractions gone!

8. anonymous

okay I was off by a lot

9. anonymous

|dw:1353193555599:dw| like this ? :S