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burhan101

  • 3 years ago

How do i get rid of this fraction ?

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  1. burhan101
    • 3 years ago
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    \[\huge \frac{ (sinx-1)-(sinx+1) }{ (sinx+1)(six-1) }\]

  2. ArkGoLucky
    • 3 years ago
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    I don't too much about sin's but don' tyou usually multiply the top and bottom by (sinx+1)(sinx-1)

  3. burhan101
    • 3 years ago
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    oh so like multiplying by one right?

  4. ArkGoLucky
    • 3 years ago
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    yes

  5. ArkGoLucky
    • 3 years ago
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    but again I don't really know this stuff so maybe you should wait for more expert advice

  6. burhan101
    • 3 years ago
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    okay, thanks :D

  7. cwrw238
    • 3 years ago
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    you can simplify this denominator = sin^2 x - 1 = - cos^2 x numerator = -2 so we get -2 / - cos^2 x = 2 / cos^2 x = 2 sec^2 x fractions gone!

  8. ArkGoLucky
    • 3 years ago
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    okay I was off by a lot

  9. burhan101
    • 3 years ago
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    |dw:1353193555599:dw| like this ? :S

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