Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 3 years ago

H9P1: (5)L=55.0H and C=7.37mF. The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=1.0s. At t=0 the state is: vC(0)=0.0 and iL(0)=1.0. The equation governing the evolution of the inductor current in this circuit is d2iL(t)dt2+1LCiL(t)=ALCδ(t−1.0) At the time just before the impulse happens what is the voltage vC(1.0−), in Volts, across the capacitor?

  • This Question is Closed

    Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy