anonymous
  • anonymous
Help me with this trig identity pleasee (
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Question please
anonymous
  • anonymous
|dw:1353194074865:dw|
anonymous
  • anonymous
simplyfy cos ^2 x... what is that now?

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anonymous
  • anonymous
clue sin^2 x + sin^2 x = 1
phi
  • phi
I think ace meant \[ \sin^2 x + \cos^2 x = 1\] I would first find a common denominator. Can you do that?
anonymous
  • anonymous
Yes @phi that is exactly what i meant XD
anonymous
  • anonymous
@aceace @phi i would get this for the right side : \[\huge =\frac{ 2 }{ 1-\sin^2x }\]
anonymous
  • anonymous
combine the LHS into 1 fraction
anonymous
  • anonymous
1-sin^2 x = cos^2 x
anonymous
  • anonymous
Common denom: sin²x -1
anonymous
  • anonymous
After simplify you'll get the result = 2/ cos²x
anonymous
  • anonymous
1/sinx+1=sinx-1/sin^2x-1 =1-sinx/1-sin^2x =1-sinx/cos^2x 1/sinx-1=sinx+1/sin^2x-1 =-1-sinx/1-sin^2x =-1-sinx/cos^2x =(1-sinx-(-1-sinx)/cos^2x =2/cos^x
anonymous
  • anonymous
sorry i was away... but that would be correct XD

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