A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353194074865:dw

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1simplyfy cos ^2 x... what is that now?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1clue sin^2 x + sin^2 x = 1

phi
 2 years ago
Best ResponseYou've already chosen the best response.0I think ace meant \[ \sin^2 x + \cos^2 x = 1\] I would first find a common denominator. Can you do that?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1Yes @phi that is exactly what i meant XD

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0@aceace @phi i would get this for the right side : \[\huge =\frac{ 2 }{ 1\sin^2x }\]

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0combine the LHS into 1 fraction

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.01sin^2 x = cos^2 x

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Common denom: sin²x 1

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1After simplify you'll get the result = 2/ cos²x

Praja_01
 2 years ago
Best ResponseYou've already chosen the best response.01/sinx+1=sinx1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x 1/sinx1=sinx+1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x =(1sinx(1sinx)/cos^2x =2/cos^x

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1sorry i was away... but that would be correct XD
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.