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burhan101
 2 years ago
Help me with this trig identity pleasee (
burhan101
 2 years ago
Help me with this trig identity pleasee (

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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1353194074865:dw

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1simplyfy cos ^2 x... what is that now?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1clue sin^2 x + sin^2 x = 1

phi
 2 years ago
Best ResponseYou've already chosen the best response.0I think ace meant \[ \sin^2 x + \cos^2 x = 1\] I would first find a common denominator. Can you do that?

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1Yes @phi that is exactly what i meant XD

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0@aceace @phi i would get this for the right side : \[\huge =\frac{ 2 }{ 1\sin^2x }\]

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0combine the LHS into 1 fraction

gohangoku58
 2 years ago
Best ResponseYou've already chosen the best response.01sin^2 x = cos^2 x

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1Common denom: sin²x 1

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.1After simplify you'll get the result = 2/ cos²x

Praja_01
 2 years ago
Best ResponseYou've already chosen the best response.01/sinx+1=sinx1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x 1/sinx1=sinx+1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x =(1sinx(1sinx)/cos^2x =2/cos^x

aceace
 2 years ago
Best ResponseYou've already chosen the best response.1sorry i was away... but that would be correct XD
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