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aceace Group TitleBest ResponseYou've already chosen the best response.1
Question please
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353194074865:dw
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.1
simplyfy cos ^2 x... what is that now?
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.1
clue sin^2 x + sin^2 x = 1
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I think ace meant \[ \sin^2 x + \cos^2 x = 1\] I would first find a common denominator. Can you do that?
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.1
Yes @phi that is exactly what i meant XD
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
@aceace @phi i would get this for the right side : \[\huge =\frac{ 2 }{ 1\sin^2x }\]
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
combine the LHS into 1 fraction
 2 years ago

gohangoku58 Group TitleBest ResponseYou've already chosen the best response.0
1sin^2 x = cos^2 x
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.1
Common denom: sin²x 1
 2 years ago

Chlorophyll Group TitleBest ResponseYou've already chosen the best response.1
After simplify you'll get the result = 2/ cos²x
 2 years ago

Praja_01 Group TitleBest ResponseYou've already chosen the best response.0
1/sinx+1=sinx1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x 1/sinx1=sinx+1/sin^2x1 =1sinx/1sin^2x =1sinx/cos^2x =(1sinx(1sinx)/cos^2x =2/cos^x
 2 years ago

aceace Group TitleBest ResponseYou've already chosen the best response.1
sorry i was away... but that would be correct XD
 2 years ago
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