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3g^2 - 12g = - 4 which number will complete the square? a. 12 b. -4 c. 4 d. 36

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if you factor out the 3 on the left, you'll get \(\large 3(g^2-4g)=-4\) Then to complete the square, add the square of half the coefficient of g.
Then, consider what would have to be added to the right side to keep both sides equal.

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Other answers:

Right, adding 4 inside the parentheses on the left yields \(\large 3(g^2-4g+4)=-4 + ?\)
so 4 completes the square then?
What happens when you distribute that 3 back into those parentheses on the left?
Right, so you actually added 12 to both sides to complete the square. \(\large 3g^2−12g+12)=−4+12\). See?
oh got it thanks!

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