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Let f(x) = x^2 + 6 and g(x) = x+8/x. Find (g times f)(-7) Choices :) A.) -55/7 B.) 384/7 C.) 295/49 D.) 63/55

Linear Algebra
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Are you sure it's "times", or is it the open circle? Which tells us that it's a composition of functions :D
It's an open circle, I looked at it wrong.
|dw:1353198866293:dw| Ok take a look at this a sec, see if it makes sense or not.. so hmmm to finish this off, we'll need to figure out what f(-7) is.

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Other answers:

How do you figure that out ?
\[\large f(x)=x^2 + 6\]\[\huge f(-7)=(-7)^2+6\]
so the answer to f(-7) is 55
Yah looks good c: So now we plug that value into g!
is the answer B, 384/7
\[f(-7)=55\]\[\huge g(f(-7))=\frac{ f(-7)+8 }{ f(-7) }=\frac{ 55+8 }{ 55 }\]
So the answer is D 63/55 :) Thank you so much
yay team :D

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