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Brooke2013

  • 2 years ago

Let f(x) = x^2 + 6 and g(x) = x+8/x. Find (g times f)(-7) Choices :) A.) -55/7 B.) 384/7 C.) 295/49 D.) 63/55

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  1. zepdrix
    • 2 years ago
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    Are you sure it's "times", or is it the open circle? Which tells us that it's a composition of functions :D

  2. Brooke2013
    • 2 years ago
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    It's an open circle, I looked at it wrong.

  3. zepdrix
    • 2 years ago
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    |dw:1353198866293:dw| Ok take a look at this a sec, see if it makes sense or not.. so hmmm to finish this off, we'll need to figure out what f(-7) is.

  4. Brooke2013
    • 2 years ago
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    How do you figure that out ?

  5. zepdrix
    • 2 years ago
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    \[\large f(x)=x^2 + 6\]\[\huge f(-7)=(-7)^2+6\]

  6. Brooke2013
    • 2 years ago
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    so the answer to f(-7) is 55

  7. zepdrix
    • 2 years ago
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    Yah looks good c: So now we plug that value into g!

  8. Brooke2013
    • 2 years ago
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    is the answer B, 384/7

  9. zepdrix
    • 2 years ago
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    \[f(-7)=55\]\[\huge g(f(-7))=\frac{ f(-7)+8 }{ f(-7) }=\frac{ 55+8 }{ 55 }\]

  10. Brooke2013
    • 2 years ago
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    So the answer is D 63/55 :) Thank you so much

  11. zepdrix
    • 2 years ago
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    yay team :D

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