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- anonymous

Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed.
(a) ... using 3 subintervals of equal width and the midpoint for sample points.
http://i48.tinypic.com/65ac1e.jpg

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- anonymous

- katieb

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- anonymous

I tried using the rieman sum midpoint but I keep getting it wrong!!!!

- anonymous

how are you supposed to divide 140 in to three sub intervals? got me.

- anonymous

It changed it to 120

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- anonymous

i guess each has length of \(46\tfrac{2}{3}\) and you take the midpoint
so first sample point would be at \(23\tfrac{1}{3}\)

- anonymous

you just ignore the 140 I guess

- anonymous

well that makes it easier

- anonymous

so it would be 30

- anonymous

no one third of 120 is 40

- anonymous

oh crap I thought it was four intervals

- anonymous

one interval would be \([0,40]\) next would be \([40,80]\) and last would be \([80,120]\) you would sample as \(20,60,100\)

- anonymous

*sample AT

- anonymous

so it would be 40[ f(20)+f(60)+f(100)]
?

- anonymous

yes that should do it

- anonymous

@satellite73 but it talks about rectangles so for each interval do I just do the X*y?

- anonymous

It's still wrong. :(

- anonymous

yes it is just rectangles, base times height

- anonymous

is the last 140,8 gone or something?

- anonymous

40[(2*20)+(4*20)+(8*20)]

- anonymous

I don't know, but this is what I did using base times height

- anonymous

and it's still wrong

- anonymous

oh i see what you did wrong

- anonymous

the base if 40, the height is 2, 4 and 8 respectively

- anonymous

you wrote \(40[ f(20)+f(60)+f(100)]\)

- anonymous

that is correct, and \(f(20)=2,f(60)=4, f(100)=8\) so it should be
\[40(2+4+8)\]

- anonymous

OH -_- wow. thanks :P I knew I was doing something too much

- anonymous

:)

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