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byerskm2

  • 3 years ago

Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed. (a) ... using 3 subintervals of equal width and the midpoint for sample points. http://i48.tinypic.com/65ac1e.jpg

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  1. byerskm2
    • 3 years ago
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    I tried using the rieman sum midpoint but I keep getting it wrong!!!!

  2. anonymous
    • 3 years ago
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    how are you supposed to divide 140 in to three sub intervals? got me.

  3. byerskm2
    • 3 years ago
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    It changed it to 120

  4. anonymous
    • 3 years ago
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    i guess each has length of \(46\tfrac{2}{3}\) and you take the midpoint so first sample point would be at \(23\tfrac{1}{3}\)

  5. byerskm2
    • 3 years ago
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    you just ignore the 140 I guess

  6. anonymous
    • 3 years ago
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    well that makes it easier

  7. byerskm2
    • 3 years ago
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    so it would be 30

  8. anonymous
    • 3 years ago
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    no one third of 120 is 40

  9. byerskm2
    • 3 years ago
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    oh crap I thought it was four intervals

  10. anonymous
    • 3 years ago
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    one interval would be \([0,40]\) next would be \([40,80]\) and last would be \([80,120]\) you would sample as \(20,60,100\)

  11. anonymous
    • 3 years ago
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    *sample AT

  12. byerskm2
    • 3 years ago
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    so it would be 40[ f(20)+f(60)+f(100)] ?

  13. anonymous
    • 3 years ago
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    yes that should do it

  14. byerskm2
    • 3 years ago
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    @satellite73 but it talks about rectangles so for each interval do I just do the X*y?

  15. byerskm2
    • 3 years ago
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    It's still wrong. :(

  16. anonymous
    • 3 years ago
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    yes it is just rectangles, base times height

  17. anonymous
    • 3 years ago
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    is the last 140,8 gone or something?

  18. byerskm2
    • 3 years ago
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    40[(2*20)+(4*20)+(8*20)]

  19. byerskm2
    • 3 years ago
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    I don't know, but this is what I did using base times height

  20. byerskm2
    • 3 years ago
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    and it's still wrong

  21. anonymous
    • 3 years ago
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    oh i see what you did wrong

  22. anonymous
    • 3 years ago
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    the base if 40, the height is 2, 4 and 8 respectively

  23. anonymous
    • 3 years ago
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    you wrote \(40[ f(20)+f(60)+f(100)]\)

  24. anonymous
    • 3 years ago
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    that is correct, and \(f(20)=2,f(60)=4, f(100)=8\) so it should be \[40(2+4+8)\]

  25. byerskm2
    • 3 years ago
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    OH -_- wow. thanks :P I knew I was doing something too much

  26. byerskm2
    • 3 years ago
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    :)

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