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byerskm2
Group Title
Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed.
(a) ... using 3 subintervals of equal width and the midpoint for sample points.
http://i48.tinypic.com/65ac1e.jpg
 one year ago
 one year ago
byerskm2 Group Title
Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed. (a) ... using 3 subintervals of equal width and the midpoint for sample points. http://i48.tinypic.com/65ac1e.jpg
 one year ago
 one year ago

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byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
I tried using the rieman sum midpoint but I keep getting it wrong!!!!
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
how are you supposed to divide 140 in to three sub intervals? got me.
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
It changed it to 120
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i guess each has length of \(46\tfrac{2}{3}\) and you take the midpoint so first sample point would be at \(23\tfrac{1}{3}\)
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
you just ignore the 140 I guess
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
well that makes it easier
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
so it would be 30
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
no one third of 120 is 40
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
oh crap I thought it was four intervals
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
one interval would be \([0,40]\) next would be \([40,80]\) and last would be \([80,120]\) you would sample as \(20,60,100\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
*sample AT
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
so it would be 40[ f(20)+f(60)+f(100)] ?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yes that should do it
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 but it talks about rectangles so for each interval do I just do the X*y?
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
It's still wrong. :(
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yes it is just rectangles, base times height
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
is the last 140,8 gone or something?
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
40[(2*20)+(4*20)+(8*20)]
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
I don't know, but this is what I did using base times height
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
and it's still wrong
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh i see what you did wrong
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the base if 40, the height is 2, 4 and 8 respectively
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
you wrote \(40[ f(20)+f(60)+f(100)]\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
that is correct, and \(f(20)=2,f(60)=4, f(100)=8\) so it should be \[40(2+4+8)\]
 one year ago

byerskm2 Group TitleBest ResponseYou've already chosen the best response.0
OH _ wow. thanks :P I knew I was doing something too much
 one year ago
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