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byerskm2 Group Title

Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed. (a) ... using 3 subintervals of equal width and the midpoint for sample points. http://i48.tinypic.com/65ac1e.jpg

  • 2 years ago
  • 2 years ago

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  1. byerskm2 Group Title
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    I tried using the rieman sum midpoint but I keep getting it wrong!!!!

    • 2 years ago
  2. satellite73 Group Title
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    how are you supposed to divide 140 in to three sub intervals? got me.

    • 2 years ago
  3. byerskm2 Group Title
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    It changed it to 120

    • 2 years ago
  4. satellite73 Group Title
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    i guess each has length of \(46\tfrac{2}{3}\) and you take the midpoint so first sample point would be at \(23\tfrac{1}{3}\)

    • 2 years ago
  5. byerskm2 Group Title
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    you just ignore the 140 I guess

    • 2 years ago
  6. satellite73 Group Title
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    well that makes it easier

    • 2 years ago
  7. byerskm2 Group Title
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    so it would be 30

    • 2 years ago
  8. satellite73 Group Title
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    no one third of 120 is 40

    • 2 years ago
  9. byerskm2 Group Title
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    oh crap I thought it was four intervals

    • 2 years ago
  10. satellite73 Group Title
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    one interval would be \([0,40]\) next would be \([40,80]\) and last would be \([80,120]\) you would sample as \(20,60,100\)

    • 2 years ago
  11. satellite73 Group Title
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    *sample AT

    • 2 years ago
  12. byerskm2 Group Title
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    so it would be 40[ f(20)+f(60)+f(100)] ?

    • 2 years ago
  13. satellite73 Group Title
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    yes that should do it

    • 2 years ago
  14. byerskm2 Group Title
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    @satellite73 but it talks about rectangles so for each interval do I just do the X*y?

    • 2 years ago
  15. byerskm2 Group Title
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    It's still wrong. :(

    • 2 years ago
  16. satellite73 Group Title
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    yes it is just rectangles, base times height

    • 2 years ago
  17. satellite73 Group Title
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    is the last 140,8 gone or something?

    • 2 years ago
  18. byerskm2 Group Title
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    40[(2*20)+(4*20)+(8*20)]

    • 2 years ago
  19. byerskm2 Group Title
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    I don't know, but this is what I did using base times height

    • 2 years ago
  20. byerskm2 Group Title
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    and it's still wrong

    • 2 years ago
  21. satellite73 Group Title
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    oh i see what you did wrong

    • 2 years ago
  22. satellite73 Group Title
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    the base if 40, the height is 2, 4 and 8 respectively

    • 2 years ago
  23. satellite73 Group Title
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    you wrote \(40[ f(20)+f(60)+f(100)]\)

    • 2 years ago
  24. satellite73 Group Title
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    that is correct, and \(f(20)=2,f(60)=4, f(100)=8\) so it should be \[40(2+4+8)\]

    • 2 years ago
  25. byerskm2 Group Title
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    OH -_- wow. thanks :P I knew I was doing something too much

    • 2 years ago
  26. byerskm2 Group Title
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    :)

    • 2 years ago
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