byerskm2
Sketch the points given. Use rectangles to estimate the distance traveled by the rocket over the first 120 seconds as directed.
(a) ... using 3 subintervals of equal width and the midpoint for sample points.
http://i48.tinypic.com/65ac1e.jpg
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byerskm2
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I tried using the rieman sum midpoint but I keep getting it wrong!!!!
anonymous
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how are you supposed to divide 140 in to three sub intervals? got me.
byerskm2
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It changed it to 120
anonymous
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i guess each has length of \(46\tfrac{2}{3}\) and you take the midpoint
so first sample point would be at \(23\tfrac{1}{3}\)
byerskm2
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you just ignore the 140 I guess
anonymous
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well that makes it easier
byerskm2
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so it would be 30
anonymous
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no one third of 120 is 40
byerskm2
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oh crap I thought it was four intervals
anonymous
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one interval would be \([0,40]\) next would be \([40,80]\) and last would be \([80,120]\) you would sample as \(20,60,100\)
anonymous
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*sample AT
byerskm2
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so it would be 40[ f(20)+f(60)+f(100)]
?
anonymous
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yes that should do it
byerskm2
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@satellite73 but it talks about rectangles so for each interval do I just do the X*y?
byerskm2
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It's still wrong. :(
anonymous
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yes it is just rectangles, base times height
anonymous
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is the last 140,8 gone or something?
byerskm2
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40[(2*20)+(4*20)+(8*20)]
byerskm2
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I don't know, but this is what I did using base times height
byerskm2
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and it's still wrong
anonymous
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oh i see what you did wrong
anonymous
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the base if 40, the height is 2, 4 and 8 respectively
anonymous
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you wrote \(40[ f(20)+f(60)+f(100)]\)
anonymous
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that is correct, and \(f(20)=2,f(60)=4, f(100)=8\) so it should be
\[40(2+4+8)\]
byerskm2
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OH -_- wow. thanks :P I knew I was doing something too much
byerskm2
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:)