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Look at the triangle.
A right angle triangle is shown with hypotenuse equal to 17 centimeters. An acute angle of the triangle is labeled as x°. The side adjacent to the acute angle has length 15 centimeters and the side opposite to the acute angle has length 8 centimeters.
What is the value of cos x°? Can someone Explain to me how to solve cos I know it is adj/hyp
 one year ago
 one year ago
Look at the triangle. A right angle triangle is shown with hypotenuse equal to 17 centimeters. An acute angle of the triangle is labeled as x°. The side adjacent to the acute angle has length 15 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of cos x°? Can someone Explain to me how to solve cos I know it is adj/hyp
 one year ago
 one year ago

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FreyesBest ResponseYou've already chosen the best response.0
Solving for x.. you would do inverse cosine on the two sides to get the angle in between the two. \[x = \cos^{1} (15/17)\]
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
Why would I inverse cos. I also have the other leg which length is 8.
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
you don't need the angle unless you are asked for it
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
They are asking for the angle
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
would it be 8 over 17 = x over 15
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
If you need the angle and not just cos of the angle, then freyes gave you a good answer. The angle is determined by the inverse trig functions. His equation gives the angle.
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
Does it matter which side is used for adj then?
 one year ago

jazyBest ResponseYou've already chosen the best response.1
dw:1353206463570:dw You want to solve for cos(x) and you already did. The answer if 15/17
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
You would use 15/17 for the cos. You could use 8/17 for the sine. Either one (and otherways, too) will give the answer, but one is for cos, the other is for sine.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
8/17 would have to be for sine because 8 is the opposite, not adjacent side.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
Yes, that's a good diagram to use. One other thing, you have to set your calculator for whether you want degrees or radians for the angle. And again, do you want the angle or just cos of the angle? Or both?
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
but that diagram shows 8 at adj and cos is adj/hyp
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
I am so to confused im sorry if I am asking a lot of questions.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
Actually, adjacent is "right next to" the little arc. It's "close by" or "right to the side". "8" is opposite, not adjacent. And don't worry about your questions, they're all good, and that's how you learn. You're doing fine.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
A good way to remember adjacent is that it shares a point with the hypotenuse that is right where the angle in question is. The angle is nestled in where the adjacent and hypotenuse meet.
 one year ago

jazyBest ResponseYou've already chosen the best response.1
It depends which angle you are looking for. Adjacent is between the right angle and the other given angle, in this case, x. dw:1353207247146:dw
 one year ago

ASpasaroBest ResponseYou've already chosen the best response.0
Then wouldnt they both be adj technicaly
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
They are adjacent depending on what angle you are looking at. If you had an angle y at the top tip, then "8" would the adjacent side for THAT angle.
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
It's wonderful when we get "aha" moments! You just learned and consolidated that learning. Well done!
 one year ago

tcarroll010Best ResponseYou've already chosen the best response.1
You are quite welcome!
 one year ago
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