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easier than you think

actually \(3^2+2^2=13\) but whatever

the original quadratic was
\[x^2-6x+13\]

m should be -6

okay so how do I get the value of m from there?

\[x^2+mx+n=0\]
\[x^2-6x+13=0\] what is \(m\)?

the original question asked for the value of m

so m is -6?

Thanks!!