A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Find any rational roots of P(x).
P(x)=3x^4+2x^39x^2+4
anonymous
 4 years ago
Find any rational roots of P(x). P(x)=3x^4+2x^39x^2+4

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try 1, 1 first then 2, 2 then 4,4 if these don't work we have to move on to fractions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there is more than 1 so even if they work there wtill might be a fraction. Oh and with this i have to show my work and do it the textbook way not by trial and error

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So what exactly is the textbook way for your textbook

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there is no other way to do it you have to check. if that is "trial and error' that is what you need to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, in practicality my teacher told me to graph the function.. and then you can use synthetic division for the ones that aren't "exact"

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But unless you have some sort of sixth sense of math you really don't have a set method.. unless your textbook does, in which case i'd want to know.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya thats the way i am just having trouble relating it to this specifc problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01 works by your eyeballs because if \[P(x)=3x^4+2x^39x^2+4\] then \[P(1)=3+29+4=0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well for this one i would guess 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0add up the coefficients and see that you get 0 then you can factor as \[(x1)\times (something)\] and then you can either factor the "something" or else use the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you only need to find one zero, then factor and end up with a quadratic, and you can always find the zeros of any quadratic

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0scratch that, this is a polynomial of degree 4, so you factor and end up with a cubic when you do that, you will see that 1 is a zero of the cubic polynomial as well, so you will factor again as \((x1)(x1)(something)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but there really isn't an exact method to it is all.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.