Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find a function f for which the limit below represents the area under f on the interval [0, a]. Here we assume the rectangles used have equal widths and right endpoints as sample points. http://i49.tinypic.com/20ua7i9.jpg

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

any guesses for this one?
no guesses? i guess \(f(x)=x^2\)
on the interval \([0,1]\) divide the interval in to \(n\) parts each of length \(\frac{1}{n}\)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Just x^2? I thought it had to be more than that though
the first simple point will be \(\frac{1}{n}\) the second will be \(\frac{2}{n}\) and the \(i\)th will be \(\frac{i}{n}\)
then for each \(i\), \(f(\frac{i}{n})=\frac{i^2}{n^2}\)
oh wow! Dang. I hate this notation. It makes it ten times more complicated than it needs to be.
multiply each by \(\frac{1}{n}\) and add the up you get \[\sum\frac{i^2}{n^3}\]
well don't be hoodwinked in to thinking these are all that easy usually it is much harder to tell
I have another one a lot like this. with a sqaure root. but I'm not sure about it
but the first clue should have been the \(i^2\) on the other hand if the interval had be \([1,2]\) it would have been completely different
interesting, because the i and n values would be different right?
because a-b / n ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question