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oh you know synthetic divison

if you have one of the roots you can divide into the polynomial to get a quadratic and solve that

No, I really dont know how to do synthetic divison :/

Oh ok.

well since x + 1 works we should try putting -1 in

\[(-1)^{3} - 3(-1)^{2} - (-1) + 3 = 0\]

c0=f(-1)=0
c1=f'(-1)=8
f_L(x)=8(x+1)

Which is that for a or b ?

a+b(x+1)
so a=0 and b=8

or ax+b
a=8 and b=8

I mean there is two questions, question a and b. I needed both of them explained to me.

on how to find them