Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

andreadesirepen

Simplify

  • one year ago
  • one year ago

  • This Question is Closed
  1. andreadesirepen
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  2. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    one way it so multiply top and bottom by \(81x^2\) to clear the complex faction after that you will factor and cancel

    • one year ago
  3. satellite73
    Best Response
    You've already chosen the best response.
    Medals 1

    first step give \[\frac{9x^2-81x}{x^2-81}\]

    • one year ago
  4. andreadesirepen
    Best Response
    You've already chosen the best response.
    Medals 0

    what do i do now?

    • one year ago
  5. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    stake out common factors. 9x^2 - 81x is the same as 9x(x-9) and x^2-81 is the same as (x+9)(x-9). Cancel the common factors and there's your answer :)

    • one year ago
  6. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    your answers should be 9x/(x+9)

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.