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DLS Group Title

PLEASE HELP!! If the line y=root 3x interests the curve x^3+y^3+3xy+5x^2+3y^2+4x+5y-1=0 At 3 points A,B,C .Then find OA*OB*OC...

  • 2 years ago
  • 2 years ago

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  1. DLS Group Title
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    |dw:1353211730667:dw| SMT lyk this?

    • 2 years ago
  2. DLS Group Title
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    @sauravshakya

    • 2 years ago
  3. sauravshakya Group Title
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    Is O the origin?

    • 2 years ago
  4. DLS Group Title
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    yes

    • 2 years ago
  5. sauravshakya Group Title
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    Is it |dw:1353224657415:dw|

    • 2 years ago
  6. DLS Group Title
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    yes

    • 2 years ago
  7. sauravshakya Group Title
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    Is it |dw:1353225679747:dw|

    • 2 years ago
  8. sauravshakya Group Title
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    @DLS

    • 2 years ago
  9. DLS Group Title
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    whatts that:o

    • 2 years ago
  10. sauravshakya Group Title
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    y=root 3x ..............i x^3+y^3+3xy+5x^2+3y^2+4x+5y-1=0 ............ii Now, From i and ii, (1+3root3)x^3 + (14+3root3)x^2 + (4+5root3)x-1=0 x^3 + (14+3root3)/(1+3root3)x^2 + (4+5root3)/(1+3root3)x -1/(1 + 3root3) =0 Now product of all the roots of this cubic equation is -1/(1+3root3) Now, OA*OB*OC = 8*3root3*product of all the roots of the above cubic equation =-24root3 /(1+3root3)

    • 2 years ago
  11. DLS Group Title
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    its 8/3root3 +1

    • 2 years ago
  12. DLS Group Title
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    \[x^3+y^3+3xy+5x^2+3y^2+4x+5y-1=0\] is the equation :(

    • 2 years ago
  13. DLS Group Title
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    \[y=\sqrt{3}x\] is the line

    • 2 years ago
  14. sauravshakya Group Title
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    oh yes it is 8/(3root3 +1) y=root 3x ..............i x^3+y^3+3xy+5x^2+3y^2+4x+5y-1=0 ............ii Now, From i and ii, (1+3root3)x^3 + (14+3root3)x^2 + (4+5root3)x-1=0 x^3 + (14+3root3)/(1+3root3)x^2 + (4+5root3)/(1+3root3)x -1/(1 + 3root3) =0 Now product of all the roots of this cubic equation is -{-1/(1+3root3)} NOTE: it is -ve since it is a cubic equation which has odd number of roots Now, OA*OB*OC = 8*product of all the roots of the above cubic equation =8/(1+3root3)

    • 2 years ago
  15. DLS Group Title
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    explain properly? ://

    • 2 years ago
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