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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1not really,but it kind of looks like a set up for integrating by parts

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0F'(x)=f(x) so we can say F'(t)=f(t) right..

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1that is what i was thinking, yes

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1maybe not exactly what you want, but you would get something like \(gF\int f g'\)

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{b \rightarrow} \int\limits_{0}^{b }G(t)F'(t)dt=\]

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0I guess enough to show that \[\int\limits f g'\] is convergent

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1first part is no problem, since \(\lim_{t\to \infty}g(t)=0\) and \(\int_a^\infty f(t)\) is bounded

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1yeah you hit the nail on the head, and frankly i don't see why that is true, so this might be the wrong approach

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1because all you know about \(g'\) is that \(g'\leq 0\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1does this come in a section after some theorem or lemma that maybe you are supposed to use?

cinar
 2 years ago
Best ResponseYou've already chosen the best response.0no, this is homework, but prof gave the hint and said that you should use integration by part..

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1well then i guess this is the right approach!
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