anonymous
  • anonymous
if cos A= 0.8 and 270 < A < 360, find the exact value of sin2A a)0.28 b)0.96 c)-0.96 d)-0.6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
Hint: sin(2A) = 2*sin(A)*cos(A) So you need to find the sin(A) first using the value of cos(A)
anonymous
  • anonymous
hmm how would i do that ?
jim_thompson5910
  • jim_thompson5910
Using the idea cos^2 + sin^2 = 1

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anonymous
  • anonymous
so .6
jim_thompson5910
  • jim_thompson5910
but it's negative because we're in quadrant IV (sine is negative here)
jim_thompson5910
  • jim_thompson5910
so sin(A) = -0.6
jim_thompson5910
  • jim_thompson5910
now use sin(2A) = 2*sin(A)*cos(A)
anonymous
  • anonymous
-.96?
jim_thompson5910
  • jim_thompson5910
yep

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