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kenneyfamily
Group Title
if cos A= 0.8 and 270 < A < 360, find the exact value of sin2A
a)0.28
b)0.96
c)0.96
d)0.6
 one year ago
 one year ago
kenneyfamily Group Title
if cos A= 0.8 and 270 < A < 360, find the exact value of sin2A a)0.28 b)0.96 c)0.96 d)0.6
 one year ago
 one year ago

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jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Hint: sin(2A) = 2*sin(A)*cos(A) So you need to find the sin(A) first using the value of cos(A)
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.1
hmm how would i do that ?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Using the idea cos^2 + sin^2 = 1
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.1
so .6
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
but it's negative because we're in quadrant IV (sine is negative here)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
so sin(A) = 0.6
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
now use sin(2A) = 2*sin(A)*cos(A)
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.1
.96?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
yep
 one year ago
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