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Rewrite the following expression as a single logarithm: (will be attached!!)

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the expression!!
answer choices A,B,C,D from top to bottom! :)
\(\huge \log a+\log b = \log ab\)

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Other answers:

the answer is A.
\(\huge \log a-\log b = \log a/b \\ \huge \log a^b=b\log a\)
how so?? can u pls show me all the steps leading u to find the answer A?
The other guy is giving you the rules. And I explained them in your other post. You divide the expressions when they have the same base and subtracted. Multiply them when they are added with the same bases. And the coefficients of the expressions become the exponents for each one.
ohh okay, thanks!! so this is my answer for sure?? answer A? the one i attached?
were u able to get that by yourself ?
yes, I am sure.
kk thanks!! :)

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