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iheartfood

  • 2 years ago

question attached inside!! :)

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  1. iheartfood
    • 2 years ago
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    part 1 of question :)

  2. iheartfood
    • 2 years ago
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    part 2 (last part!) of the question :) they are connected, but just one problem :)

  3. iheartfood
    • 2 years ago
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    A. -1 B. 27 C. 29 D. There isn't enough information to answer the question. idk :/

  4. jim_thompson5910
    • 2 years ago
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    all logs in this particular problem are base b

  5. iheartfood
    • 2 years ago
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    kk so that means? haha :P

  6. jim_thompson5910
    • 2 years ago
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) What's next?

  7. jim_thompson5910
    • 2 years ago
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    no i said that as a disclaimer to what I was about to write

  8. iheartfood
    • 2 years ago
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    oh okay haha :P so do i simplify that more? or is that the most simplified it can get?

  9. iheartfood
    • 2 years ago
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    or do i do substitution or sometihng?

  10. jim_thompson5910
    • 2 years ago
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    you can pull the exponents down

  11. jim_thompson5910
    • 2 years ago
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    using one of the rules given on that purplemath site

  12. iheartfood
    • 2 years ago
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    oh no!! i lost the link :(

  13. iheartfood
    • 2 years ago
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    can u pls resend it to me? :)

  14. jim_thompson5910
    • 2 years ago
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    http://www.purplemath.com/modules/logrules.htm

  15. iheartfood
    • 2 years ago
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    okay so which one do i use?? I'm confused :(

  16. jim_thompson5910
    • 2 years ago
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    you use the rule that log(x^y) = y*log(x)

  17. iheartfood
    • 2 years ago
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    so I'm trying to see what to put in here, but I'm stuck... idk :(

  18. jim_thompson5910
    • 2 years ago
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) Then do the proper substitutions

  19. iheartfood
    • 2 years ago
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    ohhh i see what u did now! but how do i do proper substitutions??

  20. jim_thompson5910
    • 2 years ago
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    log(A) = 5, so replace log(A) with 5 do the same with the other logs

  21. iheartfood
    • 2 years ago
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    so i get log(5)+log(2)-log(6) ??

  22. jim_thompson5910
    • 2 years ago
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    close

  23. jim_thompson5910
    • 2 years ago
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    you mixed up C and D though and you're missing your coefficients

  24. iheartfood
    • 2 years ago
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    okay then, idk then :( iheartfood=a confused person atm :/

  25. jim_thompson5910
    • 2 years ago
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    look at the givens again

  26. iheartfood
    • 2 years ago
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    the givens?

  27. iheartfood
    • 2 years ago
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    what are the givens?? from the original question?

  28. jim_thompson5910
    • 2 years ago
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    yeah, log(A) = ..., log(C) = ..., etc

  29. iheartfood
    • 2 years ago
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    okay so i get this? log(5)+log(7)-log(2) ??

  30. jim_thompson5910
    • 2 years ago
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    ok, now add on the coefficients

  31. iheartfood
    • 2 years ago
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    what coefficients?? like the results when i enter it in the calc??

  32. jim_thompson5910
    • 2 years ago
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    oh wait, idk why i said that was right, I'm misreading lol

  33. jim_thompson5910
    • 2 years ago
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) log( (A^5C^2)/(D^6) ) = 5*5 + 2*7 - 6*2 log( (A^5C^2)/(D^6) ) = ???

  34. jim_thompson5910
    • 2 years ago
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    log(A) = 5 NOT log(5)

  35. iheartfood
    • 2 years ago
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    wiat so what do i have now then?? I'm confused now lol

  36. jim_thompson5910
    • 2 years ago
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    no sry, but i put up the right way to do it

  37. iheartfood
    • 2 years ago
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    so i have this so far?|dw:1353219981709:dw|??just making sure... idk if thats how I'm supposed to draw it?

  38. jim_thompson5910
    • 2 years ago
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    hmm no

  39. jim_thompson5910
    • 2 years ago
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    that looks off

  40. iheartfood
    • 2 years ago
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    can u pls draw it for me?? idk how to comprehend that well when its like in font/text format :/

  41. jim_thompson5910
    • 2 years ago
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    \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5\right) + \log_{b}\left(C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5\log_{b}\left(A\right) + 2\log_{b}\left(C\right) - 6\log_{b}\left(D\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5(5) + 2(7) - 6(2)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = ???\]

  42. iheartfood
    • 2 years ago
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    27??

  43. iheartfood
    • 2 years ago
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    so my answer is B. 27 ???

  44. jim_thompson5910
    • 2 years ago
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    yes

  45. iheartfood
    • 2 years ago
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    thank youuu :)

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