anonymous
  • anonymous
question attached inside!! :)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
part 1 of question :)
anonymous
  • anonymous
part 2 (last part!) of the question :) they are connected, but just one problem :)
anonymous
  • anonymous
A. -1 B. 27 C. 29 D. There isn't enough information to answer the question. idk :/

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jim_thompson5910
  • jim_thompson5910
all logs in this particular problem are base b
anonymous
  • anonymous
kk so that means? haha :P
jim_thompson5910
  • jim_thompson5910
log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) What's next?
jim_thompson5910
  • jim_thompson5910
no i said that as a disclaimer to what I was about to write
anonymous
  • anonymous
oh okay haha :P so do i simplify that more? or is that the most simplified it can get?
anonymous
  • anonymous
or do i do substitution or sometihng?
jim_thompson5910
  • jim_thompson5910
you can pull the exponents down
jim_thompson5910
  • jim_thompson5910
using one of the rules given on that purplemath site
anonymous
  • anonymous
oh no!! i lost the link :(
anonymous
  • anonymous
can u pls resend it to me? :)
jim_thompson5910
  • jim_thompson5910
http://www.purplemath.com/modules/logrules.htm
anonymous
  • anonymous
okay so which one do i use?? I'm confused :(
jim_thompson5910
  • jim_thompson5910
you use the rule that log(x^y) = y*log(x)
anonymous
  • anonymous
so I'm trying to see what to put in here, but I'm stuck... idk :(
jim_thompson5910
  • jim_thompson5910
log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) Then do the proper substitutions
anonymous
  • anonymous
ohhh i see what u did now! but how do i do proper substitutions??
jim_thompson5910
  • jim_thompson5910
log(A) = 5, so replace log(A) with 5 do the same with the other logs
anonymous
  • anonymous
so i get log(5)+log(2)-log(6) ??
jim_thompson5910
  • jim_thompson5910
close
jim_thompson5910
  • jim_thompson5910
you mixed up C and D though and you're missing your coefficients
anonymous
  • anonymous
okay then, idk then :( iheartfood=a confused person atm :/
jim_thompson5910
  • jim_thompson5910
look at the givens again
anonymous
  • anonymous
the givens?
anonymous
  • anonymous
what are the givens?? from the original question?
jim_thompson5910
  • jim_thompson5910
yeah, log(A) = ..., log(C) = ..., etc
anonymous
  • anonymous
okay so i get this? log(5)+log(7)-log(2) ??
jim_thompson5910
  • jim_thompson5910
ok, now add on the coefficients
anonymous
  • anonymous
what coefficients?? like the results when i enter it in the calc??
jim_thompson5910
  • jim_thompson5910
oh wait, idk why i said that was right, I'm misreading lol
jim_thompson5910
  • jim_thompson5910
log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) log( (A^5C^2)/(D^6) ) = 5*5 + 2*7 - 6*2 log( (A^5C^2)/(D^6) ) = ???
jim_thompson5910
  • jim_thompson5910
log(A) = 5 NOT log(5)
anonymous
  • anonymous
wiat so what do i have now then?? I'm confused now lol
jim_thompson5910
  • jim_thompson5910
no sry, but i put up the right way to do it
anonymous
  • anonymous
so i have this so far?|dw:1353219981709:dw|??just making sure... idk if thats how I'm supposed to draw it?
jim_thompson5910
  • jim_thompson5910
hmm no
jim_thompson5910
  • jim_thompson5910
that looks off
anonymous
  • anonymous
can u pls draw it for me?? idk how to comprehend that well when its like in font/text format :/
jim_thompson5910
  • jim_thompson5910
\[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5\right) + \log_{b}\left(C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5\log_{b}\left(A\right) + 2\log_{b}\left(C\right) - 6\log_{b}\left(D\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5(5) + 2(7) - 6(2)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = ???\]
anonymous
  • anonymous
27??
anonymous
  • anonymous
so my answer is B. 27 ???
jim_thompson5910
  • jim_thompson5910
yes
anonymous
  • anonymous
thank youuu :)

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