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iheartfood Group Title

question attached inside!! :)

  • one year ago
  • one year ago

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  1. iheartfood Group Title
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    part 1 of question :)

    • one year ago
  2. iheartfood Group Title
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    part 2 (last part!) of the question :) they are connected, but just one problem :)

    • one year ago
  3. iheartfood Group Title
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    A. -1 B. 27 C. 29 D. There isn't enough information to answer the question. idk :/

    • one year ago
  4. jim_thompson5910 Group Title
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    all logs in this particular problem are base b

    • one year ago
  5. iheartfood Group Title
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    kk so that means? haha :P

    • one year ago
  6. jim_thompson5910 Group Title
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) What's next?

    • one year ago
  7. jim_thompson5910 Group Title
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    no i said that as a disclaimer to what I was about to write

    • one year ago
  8. iheartfood Group Title
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    oh okay haha :P so do i simplify that more? or is that the most simplified it can get?

    • one year ago
  9. iheartfood Group Title
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    or do i do substitution or sometihng?

    • one year ago
  10. jim_thompson5910 Group Title
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    you can pull the exponents down

    • one year ago
  11. jim_thompson5910 Group Title
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    using one of the rules given on that purplemath site

    • one year ago
  12. iheartfood Group Title
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    oh no!! i lost the link :(

    • one year ago
  13. iheartfood Group Title
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    can u pls resend it to me? :)

    • one year ago
  14. jim_thompson5910 Group Title
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    http://www.purplemath.com/modules/logrules.htm

    • one year ago
  15. iheartfood Group Title
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    okay so which one do i use?? I'm confused :(

    • one year ago
  16. jim_thompson5910 Group Title
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    you use the rule that log(x^y) = y*log(x)

    • one year ago
  17. iheartfood Group Title
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    so I'm trying to see what to put in here, but I'm stuck... idk :(

    • one year ago
  18. jim_thompson5910 Group Title
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) Then do the proper substitutions

    • one year ago
  19. iheartfood Group Title
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    ohhh i see what u did now! but how do i do proper substitutions??

    • one year ago
  20. jim_thompson5910 Group Title
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    log(A) = 5, so replace log(A) with 5 do the same with the other logs

    • one year ago
  21. iheartfood Group Title
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    so i get log(5)+log(2)-log(6) ??

    • one year ago
  22. jim_thompson5910 Group Title
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    close

    • one year ago
  23. jim_thompson5910 Group Title
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    you mixed up C and D though and you're missing your coefficients

    • one year ago
  24. iheartfood Group Title
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    okay then, idk then :( iheartfood=a confused person atm :/

    • one year ago
  25. jim_thompson5910 Group Title
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    look at the givens again

    • one year ago
  26. iheartfood Group Title
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    the givens?

    • one year ago
  27. iheartfood Group Title
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    what are the givens?? from the original question?

    • one year ago
  28. jim_thompson5910 Group Title
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    yeah, log(A) = ..., log(C) = ..., etc

    • one year ago
  29. iheartfood Group Title
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    okay so i get this? log(5)+log(7)-log(2) ??

    • one year ago
  30. jim_thompson5910 Group Title
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    ok, now add on the coefficients

    • one year ago
  31. iheartfood Group Title
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    what coefficients?? like the results when i enter it in the calc??

    • one year ago
  32. jim_thompson5910 Group Title
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    oh wait, idk why i said that was right, I'm misreading lol

    • one year ago
  33. jim_thompson5910 Group Title
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    log( (A^5C^2)/(D^6) ) = log(A^5C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = log(A^5) + log(C^2) - log(D^6) log( (A^5C^2)/(D^6) ) = 5*log(A) + 2*log(C) - 6*log(D) log( (A^5C^2)/(D^6) ) = 5*5 + 2*7 - 6*2 log( (A^5C^2)/(D^6) ) = ???

    • one year ago
  34. jim_thompson5910 Group Title
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    log(A) = 5 NOT log(5)

    • one year ago
  35. iheartfood Group Title
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    wiat so what do i have now then?? I'm confused now lol

    • one year ago
  36. jim_thompson5910 Group Title
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    no sry, but i put up the right way to do it

    • one year ago
  37. iheartfood Group Title
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    so i have this so far?|dw:1353219981709:dw|??just making sure... idk if thats how I'm supposed to draw it?

    • one year ago
  38. jim_thompson5910 Group Title
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    hmm no

    • one year ago
  39. jim_thompson5910 Group Title
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    that looks off

    • one year ago
  40. iheartfood Group Title
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    can u pls draw it for me?? idk how to comprehend that well when its like in font/text format :/

    • one year ago
  41. jim_thompson5910 Group Title
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    \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = \log_{b}\left(A^5\right) + \log_{b}\left(C^2\right) - \log_{b}\left(D^6\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5\log_{b}\left(A\right) + 2\log_{b}\left(C\right) - 6\log_{b}\left(D\right)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = 5(5) + 2(7) - 6(2)\] \[\Large \log_{b}\left(\frac{A^5C^2}{D^6}\right) = ???\]

    • one year ago
  42. iheartfood Group Title
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    27??

    • one year ago
  43. iheartfood Group Title
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    so my answer is B. 27 ???

    • one year ago
  44. jim_thompson5910 Group Title
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    yes

    • one year ago
  45. iheartfood Group Title
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    thank youuu :)

    • one year ago
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