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you there

yes

okay tell me what you know first?

i don't even know way to start. trig functions really confuse me

okay let me ask you do you know the unit circle?

yes!

recall the untit circle and where sin is and so forth

its the y coordinate

yes

im not sure...

that is the limit or where this anser would fall on the circle

okay now to slove the problem 4sin^2x what can be done here?

can you simplify it?

yes

to what? sorry

one sec

Quadratic formula* blah i always mix those two up.. i forget which is which :3

if you look at answers I think it is way first way

Although on a test that might not work so well :3 so you might wanna learn the method hehe

this isn't me asking this question I was trying to help only

I know, i was talking to kenney ^^ my bad

okay sorry I thought you were speaking to me

kenney too quiet -_- hehe

sorry haha just trying to read all this and take it in

but yes i understand

if we go too fast for you tell us okay

answer choices are:
a. 3π/4, 7π/4
b. π/4, 7π/4
c. π/4, 5π/4
d. 3π/4, 5π/4

if take the unit circle and find these than you can slove this that way

how will locating on the unit circle help?

if you know sin and cos and sec it's in you can use these values and use them

wait I am trying but failing to see something here??

what godo? :D

sorry i'm lost..how will the quadratic formula help?

A value that corresponds to one of the special angles i mean*

ok

zep
answers are these
a. 3π/4, 7π/4
b. π/4, 7π/4
c. π/4, 5π/4
d. 3π/4, 5π/4 help me to see this??

So cos x is a POSITIVE sqrt(2)/2 at ... pi/4.. andddd... anyone remember the other one? :D

7pi/4?

yay \:D/

thanks!!!! you guys are awesome!!! :D

zep that was what I was doing with the unit circle.

no I think thanks for the help zep I am sorry I guess I am still rusty llittle forgive me Kenndy

no worries..all help was appreciated!