hba
If cosc a =1/3t ,then tan a = ............. .



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DLS
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cosec a=1/3t
i.e sin a =3t
hypotenuse=1
height=3t
Find base with pythagoras.
tan a = height/base.

hba
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...............................

DLS
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?

Praja_01
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srry,
sin a=3t
cos a=rt(19t^2)
tan a=3t/rt(19t^2)

hba
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@Praja_01 Well you have done it right good going. :)

hba
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Thanks a lot for your help @DLS

DLS
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np :)

hba
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The answer is
\[\tan a = \frac{ 3t }{ \ \sqrt{19t^2} }\]