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baldymcgee6

Easiest way to go about taking this derivative? Power rule, chain rule and quotient rule is kind of ugly.

  • one year ago
  • one year ago

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  1. baldymcgee6
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    \[f(x) =\sqrt{\frac{ x-1}{ x+1}}\]

    • one year ago
  2. irkiz
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    chain rule first then quotient rule

    • one year ago
  3. irkiz
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    and it isnt ugly at all. The higher u go, the more 'uglier' it gets. dont be afraid of 'ugly' solutions

    • one year ago
  4. baldymcgee6
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    oops supposed to be 1-x and 1+x

    • one year ago
  5. irkiz
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    still doesnt matter just flip the sings

    • one year ago
  6. irkiz
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    |dw:1353220538034:dw|

    • one year ago
  7. irkiz
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    chain rule the exponent 1/2 then differentiate the one inside the bracket using quotient rule

    • one year ago
  8. baldymcgee6
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    |dw:1353220581666:dw|

    • one year ago
  9. irkiz
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    yup

    • one year ago
  10. baldymcgee6
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    that's ugly.

    • one year ago
  11. irkiz
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    it really isnt ugly at all... i have seen even uglier ones at my level

    • one year ago
  12. irkiz
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    just make the exponent -1/2 into a square root and put it beside the (1+x) ^2

    • one year ago
  13. irkiz
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    same with the 2 in the denominator

    • one year ago
  14. baldymcgee6
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    This is for a first derivative analysis... It is ugly to find zeroes.

    • one year ago
  15. irkiz
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    |dw:1353220820451:dw|

    • one year ago
  16. baldymcgee6
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    |dw:1353220855332:dw|

    • one year ago
  17. irkiz
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    what are you trying to find?

    • one year ago
  18. baldymcgee6
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    first and second derivative analysis

    • one year ago
  19. irkiz
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    for turning points and maximum/minimum?

    • one year ago
  20. baldymcgee6
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    max, min, inflections

    • one year ago
  21. irkiz
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    no solution then

    • one year ago
  22. baldymcgee6
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    there is a min at x=1

    • one year ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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