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baldymcgee6
Group Title
Easiest way to go about taking this derivative?
Power rule, chain rule and quotient rule is kind of ugly.
 2 years ago
 2 years ago
baldymcgee6 Group Title
Easiest way to go about taking this derivative? Power rule, chain rule and quotient rule is kind of ugly.
 2 years ago
 2 years ago

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baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
\[f(x) =\sqrt{\frac{ x1}{ x+1}}\]
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
chain rule first then quotient rule
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
and it isnt ugly at all. The higher u go, the more 'uglier' it gets. dont be afraid of 'ugly' solutions
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
oops supposed to be 1x and 1+x
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
still doesnt matter just flip the sings
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
dw:1353220538034:dw
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
chain rule the exponent 1/2 then differentiate the one inside the bracket using quotient rule
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353220581666:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
that's ugly.
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
it really isnt ugly at all... i have seen even uglier ones at my level
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
just make the exponent 1/2 into a square root and put it beside the (1+x) ^2
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
same with the 2 in the denominator
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
This is for a first derivative analysis... It is ugly to find zeroes.
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
dw:1353220820451:dw
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
dw:1353220855332:dw
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
what are you trying to find?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
first and second derivative analysis
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
for turning points and maximum/minimum?
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
max, min, inflections
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.0
no solution then
 2 years ago

baldymcgee6 Group TitleBest ResponseYou've already chosen the best response.0
there is a min at x=1
 2 years ago
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