anonymous
  • anonymous
If A=42.2degrees, B= 13.6degrees, and a=41.3, find area of triangle ABC
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
we need to see how the triangle looks like otherwise we cant say anything about it
zepdrix
  • zepdrix
|dw:1353222533411:dw| Hmm i don't think it really matters what it looks like :D we have 3 pieces, angle angle side, so we should be able to figure something out. hmmmmmmmm This is not drawn to scale, so my bad :3 just to give us a rough idea. Angle B should be much smaller though :)
zepdrix
  • zepdrix
Area, hmmmmmmmm I'm trying to rememberrrrr :3

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anonymous
  • anonymous
area of triangle = bh/2 how do you know what the height is?
anonymous
  • anonymous
nope :(
zepdrix
  • zepdrix
We could use the information we have, solve for the missing sides using the law of sines or cosines or something, and then apply heron's formula... I'm not sure that is the most efficient way though XD hehe
anonymous
  • anonymous
a)138.8 b)327.4 c)493.8 d)246.9 those are my choices
anonymous
  • anonymous
@zepdrix : Just use Tan to find the height and then use the triangle area formula.
anonymous
  • anonymous
Ohh wait. It's not a right angle triangle.
zepdrix
  • zepdrix
Yah :c
anonymous
  • anonymous
Use the law of sines then. Lot easier.
anonymous
  • anonymous
|dw:1353223094929:dw|
anonymous
  • anonymous
Solve for b which is the height and then you have everything else.
anonymous
  • anonymous
36.292 is the height right?
anonymous
  • anonymous
is 41.3 the base?
anonymous
  • anonymous
hmm thats not right
anonymous
  • anonymous
we do not know the height so use this formula Area = 1/2 ab sin(c) we need a side so use law of sines 41.3/sin(42.2) = b /sin(13.6) b = 14.4575 angle c = 180 - 42.2 - 13.6 = area = 1/2(41.3)(14.4575)sin(124.2) area = 246.93 so is D

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