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If A=42.2degrees, B= 13.6degrees, and a=41.3, find area of triangle ABC

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we need to see how the triangle looks like otherwise we cant say anything about it
|dw:1353222533411:dw| Hmm i don't think it really matters what it looks like :D we have 3 pieces, angle angle side, so we should be able to figure something out. hmmmmmmmm This is not drawn to scale, so my bad :3 just to give us a rough idea. Angle B should be much smaller though :)
Area, hmmmmmmmm I'm trying to rememberrrrr :3

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Other answers:

area of triangle = bh/2 how do you know what the height is?
nope :(
We could use the information we have, solve for the missing sides using the law of sines or cosines or something, and then apply heron's formula... I'm not sure that is the most efficient way though XD hehe
a)138.8 b)327.4 c)493.8 d)246.9 those are my choices
@zepdrix : Just use Tan to find the height and then use the triangle area formula.
Ohh wait. It's not a right angle triangle.
Yah :c
Use the law of sines then. Lot easier.
Solve for b which is the height and then you have everything else.
36.292 is the height right?
is 41.3 the base?
hmm thats not right
we do not know the height so use this formula Area = 1/2 ab sin(c) we need a side so use law of sines 41.3/sin(42.2) = b /sin(13.6) b = 14.4575 angle c = 180 - 42.2 - 13.6 = area = 1/2(41.3)(14.4575)sin(124.2) area = 246.93 so is D

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