anonymous
  • anonymous
please help me with this: The resistivity of a copper rod 50ft long and 0.25 in. in diameter is 1.76 x 10 ^-6 ohm cm at 20 Celsius. What is its resistance at -20 Celsius?
Engineering
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
The formula is: R2 = R1 ( 1 + a ( t2 - t1 ) ) R1 = 50 (Resistance no. 1) [Ohm] t1 = 20 (Temperature no. 1) [Celsius] t2 = 80 (Temperature no. 2) [Celsius] a = 0.004 (Temperature coefficient) For more info on that one check http://www.allaboutcircuits.com/vol_1/chpt_12/6.html The resistance, R, of a length of wire is described by the expression: R = ρL/A ρ = resistivity of the material composing the wire, L = length of the wire, and A = area of the conducting cross section of the wire. I guess this will do. Have fun.

Looking for something else?

Not the answer you are looking for? Search for more explanations.