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timo86m Group Title

A cat needs to figure out if it can jump across a ledge onto another legge. it weights 1 kilo and the ledge is 2 meters away. How much force does he need to make it?

  • 2 years ago
  • 2 years ago

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  1. timo86m Group Title
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    *ledge

    • 2 years ago
  2. AERONIK Group Title
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    use projectile equations to find the velocity of jump and then just use newtons second law that states force is nothing but change in momentum...

    • 2 years ago
  3. timo86m Group Title
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    a cat dont kno about newton :P

    • 2 years ago
  4. AERONIK Group Title
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    i thought you were finding the answer... so i just told you the method? are you asking how the cat knows how much force it has to apply ?

    • 2 years ago
  5. timo86m Group Title
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    trick question a cat doesn't know about newton or projectiles

    • 2 years ago
  6. AERONIK Group Title
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    will you please repeat your question ?

    • 2 years ago
  7. rajathsbhat Group Title
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    the cat does know about newtons laws!!! sure it may not know it by that name but nonetheless, it knows! Newton's laws are hardwired into it's brain & form a part of its intuition. So.... :P

    • 2 years ago
  8. MamedRifqy Group Title
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    By the way, do you want to tricking us?

    • 2 years ago
  9. Shadowys Group Title
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    As much force as it could take out. :P

    • 2 years ago
  10. shawn123 Group Title
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    if the jump makes an angle of theta with horizontal range =usquare sine2theta divided by g which is equal to 2 meters in ur question....since we assume cat is stationary before jumping he has to attain an initial velocity of so much....assuming cat knows the maximum range is obtained by jumping at 45 degrees,...he has to accelerate to this velocity before jumping....force=mass*acceleration vf=v0+at here v0=0 aceeleration =vf/t i think i dont know ....just thinking out loud.....someone may give a bette r explanation

    • 2 years ago
  11. shawn123 Group Title
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    ok force =change in momentum since mass of cat doesnt change mass of cat (vf-v0) mass of cat * initial velocity

    • 2 years ago
  12. shawn123 Group Title
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    maximum range =(v0)square /g when 45 degrees theta

    • 2 years ago
  13. shawn123 Group Title
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    maybe i confused u am a lil rusty myself

    • 2 years ago
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