Given A = 67o, B = 13o, and b = 20.3, which of the following can be used to solve the triangle?
a. Law of Sines
b. Law of Cosines
c. Hero's Formula
d. Cannot be solved.
Ah.
Law of sines:
\[\frac{\sin(a)}{A}=\frac{\sin(b)}{b}\]
Law of cosines is
\[c^2 = a^2+b^2 - 2ab\cos(C)\]
So what are you given that can be used here?
And i flipped all my capitol letters with the convention. Yes, Multiple uses of Law of sines would solve the triangle. You would have to do a 180-a-b to get angle c though...