anonymous
  • anonymous
Given A = 67o, B = 13o, and b = 20.3, which of the following can be used to solve the triangle? a. Law of Sines b. Law of Cosines c. Hero's Formula d. Cannot be solved.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
those are degrees
anonymous
  • anonymous
cosine formula is a good option
anonymous
  • anonymous
Ah. Law of sines: \[\frac{\sin(a)}{A}=\frac{\sin(b)}{b}\] Law of cosines is \[c^2 = a^2+b^2 - 2ab\cos(C)\] So what are you given that can be used here?

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anonymous
  • anonymous
cannot be solved
anonymous
  • anonymous
Sorry the law of sines should have been: \[\frac{\sin(A)}{a}=\frac{\sin(B)}{b}\]
anonymous
  • anonymous
the angles
anonymous
  • anonymous
oh and side b
anonymous
  • anonymous
Yes it can. You have 1 side and three angles
anonymous
  • anonymous
so law of sines?
anonymous
  • anonymous
And i flipped all my capitol letters with the convention. Yes, Multiple uses of Law of sines would solve the triangle. You would have to do a 180-a-b to get angle c though...

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