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kenneyfamily
 3 years ago
write an equation of a sine function with amplitude 3, period 3pi/2 and phase shift pi/4
kenneyfamily
 3 years ago
write an equation of a sine function with amplitude 3, period 3pi/2 and phase shift pi/4

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kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0is it y=3sin(3x/2pi/4)?

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0what about 3sin(4x/3pi/4)?

AERONIK
 3 years ago
Best ResponseYou've already chosen the best response.0general equation of a simple harmonic oscillator is Asin(wt). where A is the amplitude and w is the angular frequency.. amd 2pi/w is the time period...

AERONIK
 3 years ago
Best ResponseYou've already chosen the best response.0the equation you are giving should be a function of time and not distance... and by adding a minus sign you are just changing its phase by pi.

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0so my answer is wrong?

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0a. y = 3 sin (3x/2  3π/8) b. y = 3 sin (4x/3  π/3) c. y = 3 sin (4x/3  π/4) d. y = 3 sin (3x/2  π/4)

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0those are my choices @AERONIK

AERONIK
 3 years ago
Best ResponseYou've already chosen the best response.0you got me wrong friend, your choices are definitely correct....

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\huge y=a \sin(bxc)+d\]\[a=amplitude\]\[\frac{2\pi}{b}=period\]\[c=phase \; shift\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Let's figure out our b term. \[\large \frac{2\pi}{b}=\frac{3\pi}{2}\]\[\large b=\frac{4}{3}\] I hope I calculated that correctly hehe

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large y=3\sin\left(\frac{4}{3}x\frac{\pi}{4}\right)\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Mmmmm I'm not sure if I did that correctly, was I suppose to factor the 4/3 into the pi/4? I forget...

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0thats not an option :(

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0wait yes i think so

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Yah I think the b is suppose to be like this... \[\huge y=a \sin (b(xc))+d\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Which IS one of your options, if you distribute the 4/3 to the pi/4 term.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm how did you arrive at your answer? :o

kenneyfamily
 3 years ago
Best ResponseYou've already chosen the best response.0i think its b. y = 3 sin (4x/3  π/3)
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