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is it y=3sin(3x/2-pi/4)?

3sin((4/3)t+(pi/4))

what about -3sin(4x/3-pi/4)?

so my answer is wrong?

you got me wrong friend, your choices are definitely correct....

wait i'm confused

\[\huge y=a \sin(bx-c)+d\]\[a=amplitude\]\[\frac{2\pi}{b}=period\]\[c=phase \; shift\]

\[\large y=3\sin\left(\frac{4}{3}x-\frac{\pi}{4}\right)\]

thats not an option :(

Hmm

wait yes i think so

Yah I think the b is suppose to be like this...
\[\huge y=a \sin (b(x-c))+d\]

Which IS one of your options, if you distribute the 4/3 to the pi/4 term.

Hmm how did you arrive at your answer? :o

i think its b. y = 3 sin (4x/3 - π/3)

Hmmm I think so too :O