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kenneyfamily
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write an equation of a sine function with amplitude 3, period 3pi/2 and phase shift pi/4
 one year ago
 one year ago
kenneyfamily Group Title
write an equation of a sine function with amplitude 3, period 3pi/2 and phase shift pi/4
 one year ago
 one year ago

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kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
is it y=3sin(3x/2pi/4)?
 one year ago

AERONIK Group TitleBest ResponseYou've already chosen the best response.0
3sin((4/3)t+(pi/4))
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
what about 3sin(4x/3pi/4)?
 one year ago

AERONIK Group TitleBest ResponseYou've already chosen the best response.0
general equation of a simple harmonic oscillator is Asin(wt). where A is the amplitude and w is the angular frequency.. amd 2pi/w is the time period...
 one year ago

AERONIK Group TitleBest ResponseYou've already chosen the best response.0
the equation you are giving should be a function of time and not distance... and by adding a minus sign you are just changing its phase by pi.
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
so my answer is wrong?
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
a. y = 3 sin (3x/2  3π/8) b. y = 3 sin (4x/3  π/3) c. y = 3 sin (4x/3  π/4) d. y = 3 sin (3x/2  π/4)
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
those are my choices @AERONIK
 one year ago

AERONIK Group TitleBest ResponseYou've already chosen the best response.0
you got me wrong friend, your choices are definitely correct....
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
wait i'm confused
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\huge y=a \sin(bxc)+d\]\[a=amplitude\]\[\frac{2\pi}{b}=period\]\[c=phase \; shift\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Let's figure out our b term. \[\large \frac{2\pi}{b}=\frac{3\pi}{2}\]\[\large b=\frac{4}{3}\] I hope I calculated that correctly hehe
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large y=3\sin\left(\frac{4}{3}x\frac{\pi}{4}\right)\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Mmmmm I'm not sure if I did that correctly, was I suppose to factor the 4/3 into the pi/4? I forget...
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
thats not an option :(
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
wait yes i think so
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yah I think the b is suppose to be like this... \[\huge y=a \sin (b(xc))+d\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Which IS one of your options, if you distribute the 4/3 to the pi/4 term.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Hmm how did you arrive at your answer? :o
 one year ago

kenneyfamily Group TitleBest ResponseYou've already chosen the best response.0
i think its b. y = 3 sin (4x/3  π/3)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Hmmm I think so too :O
 one year ago
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