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anonymous
 3 years ago
A 0.75kg ball is attached to a 1.0m rope and whirled in a vertical circle. The rope will break when the tension exceeds 450 N. What is the maximum speed the ball can have at the bottom of the circle without breaking the rope?
anonymous
 3 years ago
A 0.75kg ball is attached to a 1.0m rope and whirled in a vertical circle. The rope will break when the tension exceeds 450 N. What is the maximum speed the ball can have at the bottom of the circle without breaking the rope?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use the equation for centripetal force and the angular velocity...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0How? Can you show please?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0at the bottom most point tension is maximum.. so substitue your value of tension in the equation t+mg=mv^2/r where r is the length of the rope, and then use energy conservation with the topmost and the bottom most point..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, i got 457.35 value for Fc. Then what to do?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0CAN YOU PLZ GIVE ME A MINUTE I WILL GIVE YOU THE LITERAL SOLUTION...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I THINK AT THE LOWEST POINT IT WILL TMG EQUALS Fc AND AT THE TOP MOST POINT IT WILL BE T+MG EQUALS F'c. HERE YOU WILL GET TWO VALUES OF V, ONE FOR THE UPPERMOST POINT AND THE OTHER FROM THE LOWEST POINT. NOW USE ENERGY CONSERVATION WHICH WILL GIVE YOU THE RELATION BETWEEN THE TWO VELOCITITES....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0IS THAT DONE FRIEND ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I could not understand. How you get two values of V?
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