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muhammadyou

A 0.75-kg ball is attached to a 1.0-m rope and whirled in a vertical circle. The rope will break when the tension exceeds 450 N. What is the maximum speed the ball can have at the bottom of the circle without breaking the rope?

  • one year ago
  • one year ago

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  1. AERONIK
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    use the equation for centripetal force and the angular velocity...

    • one year ago
  2. muhammadyou
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    How? Can you show please?

    • one year ago
  3. AERONIK
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    at the bottom most point tension is maximum.. so substitue your value of tension in the equation t+mg=mv^2/r where r is the length of the rope, and then use energy conservation with the topmost and the bottom most point..

    • one year ago
  4. muhammadyou
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    ok, i got 457.35 value for Fc. Then what to do?

    • one year ago
  5. AERONIK
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    CAN YOU PLZ GIVE ME A MINUTE I WILL GIVE YOU THE LITERAL SOLUTION...

    • one year ago
  6. muhammadyou
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    ok , sure :)

    • one year ago
  7. AERONIK
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    I THINK AT THE LOWEST POINT IT WILL T-MG EQUALS Fc AND AT THE TOP MOST POINT IT WILL BE T+MG EQUALS F'c. HERE YOU WILL GET TWO VALUES OF V, ONE FOR THE UPPERMOST POINT AND THE OTHER FROM THE LOWEST POINT. NOW USE ENERGY CONSERVATION WHICH WILL GIVE YOU THE RELATION BETWEEN THE TWO VELOCITITES....

    • one year ago
  8. AERONIK
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    IS THAT DONE FRIEND ?

    • one year ago
  9. muhammadyou
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    I could not understand. How you get two values of V?

    • one year ago
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