Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

AERONIKBest ResponseYou've already chosen the best response.0
at x=2 function is not defind.
 one year ago

AERONIKBest ResponseYou've already chosen the best response.0
so the function is discontinuous at that point.....
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
We have discontinuities whenever the DENOMINATOR is zero. So let's set the denominator equal to 0, and solve for x! Those values of X are the trouble makers! :O \[\large (x^22x)=0\]Factoring an x out of each term gives us: \[\large x(x2)=0\] Know what to do from here to solve for x? :D Need to take advantage of the Zero Factor Property! :D
 one year ago

arifelgon94Best ResponseYou've already chosen the best response.0
thnk you... but how did you solve it?
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Aeron mentioned one of the values, but there is also another one!! Make sure you don't miss that trouble maker! :3
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.