anonymous
  • anonymous
y= (2x^2 + 5) / (x^2 - 2x) point of discontinuity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
at x=2 function is not defind.
anonymous
  • anonymous
so the function is discontinuous at that point.....
zepdrix
  • zepdrix
We have discontinuities whenever the DENOMINATOR is zero. So let's set the denominator equal to 0, and solve for x! Those values of X are the trouble makers! :O \[\large (x^2-2x)=0\]Factoring an x out of each term gives us: \[\large x(x-2)=0\] Know what to do from here to solve for x? :D Need to take advantage of the Zero Factor Property! :D

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anonymous
  • anonymous
thnk you... but how did you solve it?
zepdrix
  • zepdrix
Aeron mentioned one of the values, but there is also another one!! Make sure you don't miss that trouble maker! :3

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