A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

AERONIK
 2 years ago
Best ResponseYou've already chosen the best response.0at x=2 function is not defind.

AERONIK
 2 years ago
Best ResponseYou've already chosen the best response.0so the function is discontinuous at that point.....

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1We have discontinuities whenever the DENOMINATOR is zero. So let's set the denominator equal to 0, and solve for x! Those values of X are the trouble makers! :O \[\large (x^22x)=0\]Factoring an x out of each term gives us: \[\large x(x2)=0\] Know what to do from here to solve for x? :D Need to take advantage of the Zero Factor Property! :D

arifelgon94
 2 years ago
Best ResponseYou've already chosen the best response.0thnk you... but how did you solve it?

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Aeron mentioned one of the values, but there is also another one!! Make sure you don't miss that trouble maker! :3
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.