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Convert them to exponents and then divide.
\[\sqrt[n]{a} = a^{1/n}\]

Which would then be
\[x^{\frac{1}{12}}=\sqrt[12]{x}\]

Um. No. What is \[\frac{5}{12}-\frac{1}{6}\]?

You are forgetting to put them into common denoms.
5\12 - 1\6 = 5\12 -2\12 = 3\12 = 1\4

Sure.

index 12√x^5 x index 6√x
doesn't it mean,
\(\huge \sqrt[12]{x^5} \times\sqrt[6]x\)

i hope to question was avtually to divide... its bit unclear....

*actually

yes it was. I am working on the fact that it said to divide the two expressions.

the 'x' in middle is throwing me off...

can u confirm the question abbie ?