A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
valedrine85
 3 years ago
find the surface area swept over by the portion of the parabola 9y^2=4x lying between the lines x=0 and x=1 when revolves through 2 right angles about the xaxis
valedrine85
 3 years ago
find the surface area swept over by the portion of the parabola 9y^2=4x lying between the lines x=0 and x=1 when revolves through 2 right angles about the xaxis

This Question is Open

Posideon
 3 years ago
Best ResponseYou've already chosen the best response.0revolving implies a volume

mark_o.
 3 years ago
Best ResponseYou've already chosen the best response.0.the parabola 9y^2=4x y=sqrt(4x/9) \[\int\limits_{0}^{1}\pi[\sqrt{\frac{ 4x }{ 9 }}]^{2}dx\] =\[=\pi \int\limits_{0}^{1}\frac{ 4x }{ 9 }dx\] \[=\frac{ 4\pi }{ 9 } \int\limits_{0}^{1}xdx\] can you do the next step ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.